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Rainbow [258]
2 years ago
10

Why aren't there lunar and solar eclipses every month?

Physics
2 answers:
Helga [31]2 years ago
4 0

The reason why lunar and solar eclipses do not occur every month is because; the plane of orbit of the moon around the earth is not same as that of earth around the sun.

<h3>Why don't lunar and solar eclipses occur every month?</h3>

When the Moon passes between Earth and the Sun, there's solar eclipse while when the earth passes between the Sun and the Moon, casting a shadow on the Moon, there's lunar eclipse.

Hence, because the plane of orbit of the moon around the earth is not same as that of earth around the sun, we do not have lunar and solar eclipses every month.

Read more on solar and lunar eclipse;

brainly.com/question/14198324

#SPJ11

Shalnov [3]2 years ago
3 0

The moon's orbital plane is different from that of the earth's orbit around the sun due to which lunar and solar eclipses do not occur every month.

<h3 /><h3>What is a solar eclipse?</h3>

When the moon passes in front of Earth and the sun, it creates a solar eclipse and casts a shadow across the globe.

Only during the new moon phase, when the moon travels squarely between the sun and Earth and casts shadows on its surface, can a solar eclipse occur.

Due to the moon's orbit being five degrees off-center from Earth's orbit around the Sun, lunar eclipses do not happen every month and the Moon often passes above or below the shadow.

Lunar eclipses would happen every month if there were no tilt. Eclipses of the sun and the moon happen equally often.

Hence lunar and solar eclipses aren't coming every month.

To learn more about the solar eclipse refer;

brainly.com/question/17749647

#SPJ1

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A negative charge of -6.0x10-6 C exerts an
Ray Of Light [21]

The magnitude of the second charge given that the first is –6×10¯⁶ C and is located 0.05 m away is +3.0×10¯⁶ C

<h3>Coulomb's law equation </h3>

F = Kq₁q₂ / r²

Where

  • F is the force of attraction
  • K is the electrical constant
  • q₁ and q₂ are two point charges
  • r is the distance apart

<h3>How to determine the second charge </h3>
  • Charge 1 (q₁) = –6×10¯⁶ C
  • Electric constant (K) = 9×10⁹ Nm²/C²
  • Distance apart (r) = 0.05 m
  • Force (F) = 65 N
  • Charge 2 (q₂) =?

F = Kq₁q₂ / r²

Cross multiply

Fr² = Kq₁q₂

Divide both side by Kq₁

q₂ = Fr² / Kq₁

q₂ = (65 × 0.05²) / (9×10⁹ × 6×10¯⁶)

q₂ = +3.0×10¯⁶ C (since the force is attractive)

Learn more about Coulomb's law:

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Two simple pendulums are in two different places. The length of the second pendulum is 0.4 times the length of the first pendulu
faltersainse [42]

Answer:

\sqrt{\frac{4}{9}}

Explanation:

The frequency of a simple pendulum is given by:

f=\frac{1}{2\pi}\sqrt{\frac{g}{L}}

where

g is the acceleration of gravity

L is the length of the pendulum

Calling L_1 the length of the first pendulum and g_1 the acceleration of gravity at the location of the first pendulum, the frequency of the first pendulum is

f_1=\frac{1}{2\pi}\sqrt{\frac{g_1}{L_1}}

The length of the second pendulum is 0.4 times the length of the first pendulum, so

L_2 = 0.4 L_1

while the acceleration of gravity experienced by the second pendulum is 0.9 times the acceleration of gravity experienced by the first pendulum, so

g_2 = 0.9 g_1

So the frequency of the second pendulum is

f_2=\frac{1}{2\pi}\sqrt{\frac{g_2}{L_2}}=\frac{1}{2\pi} \sqrt{\frac{0.9 g_1}{0.4 L_1}}

Therefore the ratio between the two frequencies is

\frac{f_1}{f_2}=\frac{\frac{1}{2\pi}\sqrt{\frac{g_1}{L_1}}}{\frac{1}{2\pi} \sqrt{\frac{0.9 g_1}{0.4 L_1}}}=\sqrt{\frac{0.4}{0.9}}=\sqrt{\frac{4}{9}}

8 0
3 years ago
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