Answer:
A 200mm lever and a 240 mm diameter pulley are welded to the axle BE that is supported by bearings at C and D. If a 860N vertical load is applied at A when the lever is horizontal, determine (a)the tension in the cord, (b)the reactions at C and D. assume that the bearing at D does not exert axial thrust.
see explanation
Explanation:
Part a
The tension in the cord

860(200) - T(120) = 0
T(120) = 172000
T =1433.33N
The tension in the cord (T) = 1433.33N
Part b
Apply the moment law of equilibrium at point D about y-axis.


sustitute 1433.33N for T

The reaction at C along x-axis 477.78N
Apply the moment law of equilibrium at point D about x-axis


The reaction at C along y-axis is 143.33N
Apply the force law of equilibrium along z direction.


The reaction at C along z-axis is 0N
Apply the force law of equilibrium along x direction.


substitute 477.78N for
and 143.33N for 

The reaction at D along x-axis is -1911.11 N
Apply the force law of equilibrium along y direction.


substitute 1433.33 for 
