Answer:
d
Explanation:
is the because that's the amount of work in making machine can do producing heat
B I guess. since they both have potential to collapse
Answer:21.3%
Explanation:
Given
80 % reduction in tool life
According to Taylor's tool life
=c
where V is cutting velocity
T=tool life of tool
80 % tool life reduction i.e. New tool Life is 0.2T
Thus
=1.213V
Thus a change of 21.3 %(increment) is required to reduce tool life by 80%
Answer:
hypoeutectoid
Explanation:
ferrite: pure form of iron
cementite: It is iron carbide with 93.3% iron and 6.67% carbon
hypoeutectoid: Eutectoid steel with carbon fraction less than 0.8%
hypereutectoid: Eutectoid Steel with carbon content more than 0.8%
For the mentioned iron-carbide alloy,
% of carbon in iron-carbide alloy= percentage of cementite × percentage of carbon in cementite
% of carbon in iron-carbide alloy= 0.09× 0.0667
= 0.6%
so the alloy is hypoeutectoid
Answer:
Unit test
Explanation:
Defintion: A test of each individual component (often a program) to ensure that it is as defect-free as possible.
