Answer:
. Heat transfer can be higher if themal efficiency is lower.
Explanation:
The heat transfer rate to the river water is calculated by this expression:
![\dot Q_{L} = \dot Q_{H} - \dot W](https://tex.z-dn.net/?f=%5Cdot%20Q_%7BL%7D%20%3D%20%5Cdot%20Q_%7BH%7D%20-%20%5Cdot%20W)
![\dot Q_{L} = (\frac{1}{\eta_{th}}-1 )\cdot \dot W\\\dot Q_{L} = (\frac{1}{0.54}-1)\cdot (600 MW)\\\dot Q _{L} = 511.111 MW](https://tex.z-dn.net/?f=%5Cdot%20Q_%7BL%7D%20%3D%20%28%5Cfrac%7B1%7D%7B%5Ceta_%7Bth%7D%7D-1%20%29%5Ccdot%20%5Cdot%20W%5C%5C%5Cdot%20Q_%7BL%7D%20%3D%20%28%5Cfrac%7B1%7D%7B0.54%7D-1%29%5Ccdot%20%28600%20MW%29%5C%5C%5Cdot%20Q%20_%7BL%7D%20%3D%20511.111%20MW)
The actual heat transfer can be higher if the steam power plant reports an thermal efficiency lower than expected.
Answer:
cultivation - preparing and planting crops
domestication - capturing, taming, and breeding animals
hunting and gathering - obtaining food from the wild
Explanation:
moo
Answer:
the crown is false densty= 12556kg/m^3[/tex]
Explanation:
Hello! The first step to solve this problem is to find the mass of the crown, this is found using the weight of the crown in the air by means of the equation for the weight.
W=mg
W=weight(N)=31.4N
M=Mass
g=gravity=9.81m/S^2
solving for M
m=W/g
![m=\frac{31.4N}{9.81m/S^2}=3.2kg](https://tex.z-dn.net/?f=m%3D%5Cfrac%7B31.4N%7D%7B9.81m%2FS%5E2%7D%3D3.2kg)
The second step is find the volume of crown remembering that when an object is weighed in the water the result is the subtraction between the weight of the object and the buoyant force of the water which is the product of the volume of the crown by gravity by density of water
![F=mg-\alpha V g](https://tex.z-dn.net/?f=F%3Dmg-%5Calpha%20%20V%20g)
Where
F=weight in water=28.9N
m=mass of crown=3.2kg
g=gravity=9.81m/S^2
α=density of water=1000kg/m^3
V= crown´s volume
solving for V
![V=\frac{mg-F }{g \alpha } =\frac{(3.2)(9.81)-28.9}{9.81(1000)} =0.000254m^3](https://tex.z-dn.net/?f=V%3D%5Cfrac%7Bmg-F%20%7D%7Bg%20%5Calpha%20%7D%20%3D%5Cfrac%7B%283.2%29%289.81%29-28.9%7D%7B9.81%281000%29%7D%20%3D0.000254m%5E3)
finally, we remember that the density is equal to the index between mass and volume
![\alpha =\frac{m}{v} =\frac{3.2}{0.000254} =12556kg/m^3](https://tex.z-dn.net/?f=%5Calpha%20%3D%5Cfrac%7Bm%7D%7Bv%7D%20%3D%5Cfrac%7B3.2%7D%7B0.000254%7D%20%3D12556kg%2Fm%5E3)
To determine the density of the crown without using the weight in the water and with a bucket we can use the following steps.
1.weigh the crown in the air and find the mass
2. put water in a cylindrical bucket and measure its height with a ruler.
3. Put the crown in the bucket and measure the new water level with a ruler.
4. Subtract the heights, and find the volume of a cylinder knowing the difference in heights and the diameter of the bucket, in order to determine the volume of the crown.
5. find density by dividing mass by volume
Answer:
1700kJ/h.K
944.4kJ/h.R
944.4kJ/h.°F
Explanation:
Conversions for different temperature units are below:
1K = 1°C + 273K
1R = T(K) * 1.8
= (1°C + 273) * 1.8
1°F = (1°C * 1.8) + 32
Q/delta T = 1700kJ/h.°C
T (K) = 1700kJ/h.°C
= 1700kJ/K
T (R) = 1700kJ/h.°C
= 1700kJ/h.°C * 1°C/1.8R
= 944.4kJ/h.R
T (°F) = 1700kJ/h.°C
= 1700kJ/h.°C * 1°C/1.8°F
= 944.4kJ/h.°F
Note that arithmetic operations like subtraction and addition of values do not change or affect the value of a change in temperature (delta T) hence, the arithmetic operations are not reflected in the conversion. Illustration: 5°C - 3°C
= 2°C
(273+5) - (273+3)
= 2 K