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defon
2 years ago
8

A rare butterfly (0.01 kg) is slowly flapping its wings and moving across a road. An unsuspecting driver in a large car (1000 kg

) going very fast makes a sharp turn and runs directly into the butterfly. The butterfly smashes against the windshield (of course) but the car keeps moving down the road. Which object has the greater force: The butterfly or the car?
Physics
1 answer:
aliya0001 [1]2 years ago
8 0

Both the butterfly and the large car will have equal forces but in opposite direction.

<h3>Newton's third law of motion</h3>

Newton's third law of motion states that action and reaction are equal and opposite. That is, the force exerted on an object is equal to the reaction experienced by the object.

Fa = - Fb

where;

  • Fa is the force exerted by the large car
  • Fb is the force of the butterfly

Thus, both the butterfly and the large car will have equal forces but in opposite direction.

Learn more about Newton's third law of motion here: brainly.com/question/25998091

#SPJ1

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An unmanned spacecraft travels to Mars. Mars has a lower strength of gravity than Earth. Where in the image is the spacecraft’s
elena-14-01-66 [18.8K]

Answer:

First Dot That is located on Earth.

Explanation:

Due to Earth's gravity being greater than the moon's on earth there is more gravitational force pulling down on the spacecraft.

3 0
4 years ago
Need some help plsss!
RoseWind [281]

Answer:

1and4attract and1and 2repel

6 0
3 years ago
Two slits separated by a distance of d = 0.190 mm are located at a distance of D = 1.91 m from a screen. The screen is oriented
Svetlanka [38]

Answer:

\theta = 0.195^0

Explanation:

wavelength \lambda  = 648 nm \   = 648*10^{-9}m

d = 0.190 mm = 0.190 × 10⁻³ m

D = 1.91 m

By using the formula:

dsin \theta = n \lambda\\\\\theta = sin^{(-1)}(\frac{n \lambda}{d})\\\\\\\theta = sin^{(-1)}(\frac{1*648*10^{-9}}{0.190*10^{-3}})

\theta = 0.195^0

The first maximum will appear at an angle \theta = 0.195^0 from the beam axis

3 0
3 years ago
A wire of a given material has an electric field of 0.100 mV/m when a potential is applied. The wire has 8.49 x 1028 conduction
Bond [772]

The uniform current density in the wire is 5.43 x 10²⁷ A/m².

<h3>Current density in the wire</h3>

The uniform current density in the wire is calculated as follows;

J = total current / total area

The given parameters:

  • Conduction of the wire = 8.49 x 10²⁸ e/m²
  • time, t = 2.5 x 10⁻¹⁴ s

J = \frac{I}{A} = \frac{Q}{At} \\\\J = \frac{8.49 \times 10^{28}e/m^3 \ \times \ 1.6 \times 10^{-19} \ C/e}{2.5 \times 10^{-14} \ s \ \times ( 0.1 \times 10^{-3} \ V/m)} \\\\J = 5.43 \times 10^{27} \ A/m^2

Learn more about current density here: brainly.com/question/15266434

#SPJ1

3 0
2 years ago
Find the current through a person and identify the likely effect on her if she touches a 120 V AC source in the following circum
QveST [7]

Answer:

A) 0.4 mA

B) 0.03 mA

Explanation:

Given that

voltage source, V = 120 V

to solve this question, we would be using the very basic Ohms Law, that voltage is proportional to the current and the resistance passing through the circuit, if temperature is constant.

mathematically, Ohms Law, V = IR

V = Voltage

I = Current

R = Resistance

from question a, we were given 300kΩ, substituting this value of resistance in the equation, we have

120 = I * 300*10^3 Ω

making I the subject of the formula,

I = 120 / 300000

I = 0.0004 A

I = 0.4 mA

Question said, currents above 10 mA causes involuntary muscle contraction, this current is way below 10 mA, so nothing happens.

B, we have Resistance, R = 4000kΩ

Substituting like in part A, we have

120 = I * 4000*10^3 Ω

I = 120 / 4000000

I = 0.00003 A

I = 0.03 mA

This also means nothing happens, because 0.03 mA is very much lesser compared to in the 10 mA

5 0
3 years ago
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