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coldgirl [10]
2 years ago
12

A semipermeable membrane is placed between the following solutions. Which solution will decrease in volume?.

Chemistry
1 answer:
Ivan2 years ago
6 0
Solution a : 1.4% (m/v) starch
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Formaldehyde is a carcinogenic volatile organic compound with a permissible exposure level of 0.75 ppm. At this level, how many
Flauer [41]

Answer : The amount of formaldehyde permissible are, 5.4\times 10^{-6}g

Explanation : Given,

Density of air = 1.2kg/m^3=1.2g/L     (1kg/m^3=1g/L)

First we have to calculate the mass of air.

\text{Mass of air}=\text{Density of air}\times \text{Volume of air}

\text{Mass of air}=1.2g/L\times 6.0L

\text{Mass of air}=7.2g

Now we have to calculate the amount of formaldehyde.

Permissible exposure level of formaldehyde = 0.75 ppm = \frac{0.75g\text{ of formaldehyde}}{10^6g\text{ of air}}

Amount of formaldehyde in 7.2 g of formaldehyde = 7.2g\times \frac{0.75g\text{ of formaldehyde}}{10^6g\text{ of air}}

Amount of formaldehyde in 7.2 g of formaldehyde = 5.4\times 10^{-6}g

Thus, the amount of formaldehyde permissible are, 5.4\times 10^{-6}g

8 0
3 years ago
If you have 15g of sodium carbonate, what<br> mass of sodium is present in that sample?
Sati [7]

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Explanation:

5 0
3 years ago
I will mark brainliest
blondinia [14]

Answer:

1. sovent

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3 0
2 years ago
An object was measured by a worker as
Gre4nikov [31]

Answer:

\boxed{2.8 \, \%}

Explanation:

\text{Percent error} = \dfrac{\lvert \text{Measured - Actual}\lvert}{ \text{Actual}} \times100 \, \%

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Calculation:

\text{Percent error} = \dfrac{\lvert 17.4 - 17.9\lvert}{17.9} \times 100 \, \% \\\\= \dfrac{\lvert-0.5\lvert}{17.9} \times 100 \, \% = \dfrac{0.5}{17.9} \times 100 \, \% \\\\= 0.028 \times 100 \, \% = \textbf{2.8 \%}\\\\\text{The percent error in the measurement is } \boxed{\textbf{2.8 \%}}

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3 years ago
5 Um vidro contém 300 cm3 de mercúrio de densidade 13 g/cm3. Qual é massa de mercúrio contido no vidro?
GaryK [48]

Answer:

130

Explanation:

This is because I just took the test and it said this was the answer

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3 years ago
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