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JulijaS [17]
2 years ago
14

A charge of 5.67 x 10^-18 C is placed 3.5 x 10^-6 m away from another charge of -

Physics
1 answer:
Fudgin [204]2 years ago
5 0
+ 1.58 e -15

Please hit thanks button! :)
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Two obiect accumulated a charge of
tamaranim1 [39]

Answer:

A. 181.24 N

Explanation:

The magnitude of hte electrostatic force between two charged objects is given by the equation

F=k\frac{q_1 q_2}{r^2}

where

k is the Coulomb's constant

q1, q2 are the magnitudes of the two charges

r is the separation between the charges

In this problem, we have:

q_1=4.5\mu C=4.5\cdot 10^{-6}C is the magnitude of the 1st charge

q_2=2.8\mu C=2.8\cdot 10^{-6}C is the magnitude of the 2nd charge

r = 2.5 cm = 0.025 m is the separation between the charges

Therefore, the magnitude of the electric force is:

F=\frac{(9\cdot 10^9)(4.5\cdot 10^{-6})(2.8\cdot 10^{-6})}{(0.025)^2}=181.44 N

So, the closest answer is

A) 181.24 N

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Answer:

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A coworker did not clean his work area before going home this could cause an accident so you quickly clean up the next day you s
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It results change only in it's kinetic energy, it's KE will increase in accord with the work-energy theorem 
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