Answer:
Ionic.
Explanation:
To know the the correct answer to the question given above, let us define the terms covalent and ionic.
Covalent is the term used to characterise a compound which is formed by sharing of electrons between the atoms involved. Thus, the compound formed is called covalent compound.
Ionic is the term used to characterise a compound formed when there is a transfer of electron(s) from the metallic atom to the non-metallic atom. The compound formed is called ionic compound.
Considering the question given above, since the calcium atom transfer electron(s) to the carbon atom, it means the compound is an ionic compound.
Answer:
b ac power source
Explanation:
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Answer:
the scattering of short wavelengths as light
passes through the atmosphere
the Axis Perpendicular to the Length and Passing through the Center. Take a uniform thin rod AB whose mass is M and length is l. YY’ axis passes through the center of the rod and perpendicular to the length of the rod. We have to calculate the moment of inertia about this axis. YY’.
Suppose, small piece dx is at a distance x from the YY' axis. Hence, mass of length dx is =(
l
M
)dx The moment of inertia of small piece about the YY' axis
dl=[(
l
M
)dx]x
2
Therefore, the moment of inertia of the complete rod about the YY' axis.
b) Moment of Inertia about the axis perpendicular to the the length and passing through the Corner If I
CD
is the moment of inertia about the axis CD perpendicular to the length of a thin rod and passing through the point A then, by theorem of parallel axis;
l
CD
=l
YY
′
+Md
2
=
12
Ml
2
+M(
2
l
)
2
l
CD
=
3
Ml
2
.........(2)
Answer:
the angular acceleration is 9.7 rad/
Explanation:
given information:
mass of thin rod, m = 3.2 kg
the length of the rod, L = 1.2
angle, θ = 38
to find the acceleration of the rod, we can use the torque's formula as below,
τ = Iα
where
τ = torque
I = inertia
σ = acceleration
moment inertia of this rod, I
I = 
τ = F d, d = 
cosθ
τ = m g cosθ
now we can substitute the both equation,
τ = Iα
α = τ/I
= (m g cosθ)/()
= 3gcosθ/2L
= 3 (9.8)cos 38°/(2 x 1.2)
= 9.7 rad/
