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3 years ago

15

During the winter, what type of precipitation would most likely fall in New York, with temperatures averaging 32 F?

2 answers:

Nady [450]3 years ago

5 0

During the winter, what type of precipitation would most likely fall in New York, with temperatures averaging 32°F?

A.) rain

B.) sleet

C.) snow

D.) drizzle

(Answer choice C.)

alukav5142 [94]3 years ago

4 0

<span>The correct answer should be snow. Snow falls when the temeprature is 32F or 0C. It doens't fall when temperatures are higher because the water vapor doens't crystalize, and it often doesn't fall when the temperature is much lower either. Sleet is that weird mixture between snow and rain that falls when temperature goes down but is not yet low enough for full snow to go down.</span>

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What is the weight of an object with a mass of 6.0 kg on Earth?

gregori [183]

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6 x 9.807
= 58.842 N

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a bal is launched upward with a velocity of v0 from the edge of a cliff of height D. it reaches a maximum height of H above its

lilavasa [31]

Answer:

D/H =15

Explanation:

We can find first the peak height H, taking into consideration, that at the maximum height, the ball will reach momentarily to a stop.
At this point, we can find the value of H, applying the following kinematic equation:

$v_{f} ^{2} -v_{0} ^{2} = 2* g* H (1)$

If vf=0, if we assume that the positive direction is upwards, we can find the value of H as follows:

$H = \frac{v_{0} ^{2} }{2*g} (2)$

We can use the same equation, to find the value of D, as follows:

$v_{f} ^{2} -v_{1} ^{2} = 2* g* D (3)$

In order to find v₁, we can use the same kinematic equation that we used to get H, but now, we know that v₀ = 0.
When we replace these values in (1), we find that v₁ = -v₀.
Replacing in (3), we have:

$(4*v_{0})^{2} - (-v_{0}) ^{2} = 2* g* D\\ \\ 15*v_{0}^{2} = 2*g*D$

Solving for D:

$D = \frac{15*v_{0} ^{2} }{2*g}$

From (2) we know that H can be expressed as follows:

$H = \frac{v_{0} ^{2} }{2*g}$

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$\frac{D}{H} = 15$

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3 years ago

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mixer [17]

Work equals force × displacement (distance between initial point and end point is displacement)
if u follow this it becomes
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comment if u have more questions

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3 years ago

The diameter of an atom is 1.1×10−10m and the diameter of its nucleus is 1.0×10−14m. Part A What percent of the atom's volume is

77julia77 [94]

To solve this problem we will use the basic concept given by the Volume of a sphere with which the atom approaches. The fraction in percentage terms would be given by the division of the total volume of the nucleus by that of the volume of the atom, that is,

$\% Percent = \frac{V_{nucleus}}{V_{atom}}*100$

$\% Percent = \frac{4/3 \pi (d_{nucleus}/2)^3}{4/3 \pi (d_{atom}/2)^3}*100$

$\% Percent = \frac{(d_{nucleus}/2)^3}{ (d_{atom}/2)^3}*100$

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$\% Percent = 7.51*10^{-11}\%$

Therefore the percent of the atom's volume is occupied by mass is $7.51*10^{-11}\%$

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3 years ago