Answer:
0.572
Explanation:
The formula for ammonium nitrate is
NH4NO3
The trick here is to realize the 4 applies only to the hydrogen. The 3 applies only to the oxygen.
There are 2 nitrogens in the formula. So if the entire molecule represents 0.286 mols. The individual mols of each part of the formula is just multiplied by the number of moles of the molecule. In formula form
Number of moles of the atoms making up the molecule = number of atoms from the formula * mols of the molecule.
2*0.286 = 0.572 moles of Nitrogen
Answer:- 14.0 moles of hydrogen present in 2.00 moles of .
Solution:- We have been given with 2.00 moles of and asked to calculate the grams of hydrogen present in it. It's a two step conversion problem. In first step we convert the moles of the compound to moles of hydrogen as one mol of the compound contains 7 moles of hydrogen. In next step the moles are converted to grams on multiplying the moles by atomic mass of H. The calculations are shown as:
= 14.0 g H
So, there are 14.0 g of hydrogen in 2.00 moles of .
Answer:
102.8 kPa.
Explanation:
- We can use the general law of ideal gas: <em>PV = nRT.</em>
where, P is the pressure of the gas in atm (P = ??? atm).
V is the volume of the gas in L (V = 4000 mL = 6.23 L).
n is the no. of moles of the gas in mol (n = 0.25 mol).
R is the general gas constant (R = 0.0821 L.atm/mol.K),
T is the temperature of the gas in K (T = 35ºC + 273 = 308 K).
∴ P = nRT/V = (0.25 mol)(0.0821 L.atm/mol.K)(308 K)/(6.23 L) = 1.015 atm.
<em><u>multiply the pressure value by 101.325
</u></em>
∴ P = (1.0 atm)(101.325 kPa/1.0 atm) = 102.8 kPa.
Partial would be the answer your looking for
Answer:
it the Aquarius of the ph solution
Explanation: