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alex41 [277]
2 years ago
5

If a utility burned 7.57 million tons of coal that was 2.00% sulfur by weight, how many tons of sulfur dioxide were emitted? Ans

wer in scientific notation.
Chemistry
2 answers:
FromTheMoon [43]2 years ago
7 0

So mass of sulphur

\\ \rm\Rrightarrow 0.02\times 757\times 10^{6}

\\ \rm\Rrightarrow 1514\times 10^4

  • S+O_2–≥SO_2

Moles =64/32=2

So

So tons of sulphur dioxide

\\ \rm\Rrightarrow 2(1516)10^4

\\ \rm\Rrightarrow 3032\times 10^4ton

Anestetic [448]2 years ago
5 0

Explanation:

2% of 2million tons of sulphur=

2÷100×7.57E9

That is;

\frac{2}{100}  \times 7.57 \times 10 {}^{6}  = 0.02 \times 7.57 \times 10 {}^{6}  \\  = 2 \times 10 {}^{ - 2}  \times7.57 \times 10 {}^{6}   = 2 \times 7.57(10 {}^{ - 2 + 6}) \\  = 15.14 \times 10 {}^{4} (for \: sulphur) \\ for \: sulphur \: dioxide = so2 \\ the \: molar \: mass \: of \: so2 = 64g.mol {}^{ -1}  \\ if \: 32grams \: of \: sulphur \: weighs \: 15.14 \times 10 {}^{4} tones \\ 64grams \: will \: weigh \:  \frac{64}{32} \times 15.14 \times 10 {}^{4}   \\  = 2 \times 15.14 \times 10 {}^{4}  \\  = 30.28 \times 10 {}^{4}  \\ or = 3.028 \times 10 {}^{5} tones

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