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Leno4ka [110]
2 years ago
10

Sr 32.8 g, Si 5.2 g and O 11.9 g empirical formula number 11

Chemistry
1 answer:
horsena [70]2 years ago
8 0

\boxed{\begin{array}{c|c|c|c|c}\boxed{\sf Element}&\boxed{\sf Mass\:in\: compound}&\boxed{\sf No\:of\:moles}&\boxed{\sf Ratio}&\boxed{\sf Simplified\:ratio}\\ \sf Sr &\sf 32.8g &\sf \dfrac{32.8}{87}=0.37&\sf \dfrac{0.37}{0.18}=2.05&\sf 2 \\ \sf Si &\sf 5.2g &\sf \dfrac{5.2}{28}=0.18 &\sf \dfrac{0.18}{0.18}=1&\sf 1\\ \sf O&\sf 11.9g &\sf \dfrac{11.9}{16}=0.74&\sf\dfrac{0.74}{0.18}=4.1 &\sf 4\end{array}}

Empirical formula:-

\\ \sf\longmapsto SiSr_2O_4

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15. What volume of CCI, (d = 1.6 g/cc) contain
anastassius [24]

Answer:

\boxed{\text{(3) 9.6 L}}

Explanation:

1. Moles of CCl₄

n = 6.02 \times 10^{25} \text{ molecules} \times \dfrac{\text{1 mol}}{6.022 \times 10^{23}\text{ molecules}} = \text{100.0 mol}

2. Molar mass of CCl₄

MM = 1 × 12.01 + 4 × 35.5 = 12.01 + 142 = 154.0 g/mol

3. Mass of CCl₄

m =\text{100.0 mol} \times \dfrac{\text{154.0 g}}{\text{1 mol}} = \text{15 400 g}

4. Volume of CCl₄

V = \text{15 400 g} \times \dfrac{\text{1 cm}^{3}}{\text{1.6 g}} = \text{9600 cm}^{3}\\\\V = \text{9600 cm}^{3} \times \dfrac{\text{1 L}}{\text{1000 cm}^{3}} = \mathbf{{9.6 L}}\\\\\text{The volume of CCl$_{4}$ is } \boxed{\textbf{9.6 L}}

4 0
3 years ago
2. What are the factors that influence the two types of energy?
VikaD [51]

Answer:

It depends on the objects mass, the gravitational pull when up or down slopes, and the height of the reference point

3 0
2 years ago
How many moles of chloride ions are there in 2.5 L of 5 M magnesium chloride?
castortr0y [4]

Answer:

n_{Cl^-}=25molCl^-

Explanation:

Hello,

In this case, since the given 5-M concentration of magnesium chloride is expressed as:

5\frac{molMgCl_2}{L}

We can notice that one mole of salt contains two moles of chloride ions as the subscript of chlorine is two, in such a way, with the volume of solution we obtain the moles of chloride ions as shown below:

n_{Cl^-}=5\frac{molMgCl_2}{L}*\frac{2molCl^-}{1molMgCl_2} *2.5L\\\\n_{Cl^-}=25molCl^-

Best regards.

4 0
3 years ago
What is 1006 in scientific notation?
vladimir1956 [14]

Answer:

1.006 * 103

Explanation:

Add the number between 1 and 9 and add a decimal accordingly . so the answer is 1.006 multiplied by 10 raised to power 3

8 0
3 years ago
At a particular temperature, 12.0 moles of so3 is placed into a 3.0-l rigid container, and the so3 dissociates by the reaction 2
saul85 [17]
            2 SO₃ --> 2 SO₂ + O₂
I             12             0          0
C           -2x           +2x      +x
---------------------------------------------
E         12-2x          2x         x

Since the moles of SO₂ at equilibrium is 3 mol, 2x = 3. Then, x = 1.5 mol. So, the amounts at equilibrium is:
SO₃: 12 - 2(1.5) = 9
SO₂: 2(1.5) = 3
O₂: 1.5

The formula for K basing on the stoichiometric reaction is:
K = [SO₂]²[O₂]/[SO₃]² 
where the unit used is conc in mol/L.

K = [3 mol/3 L]²[1.5 mol/3 L]/[9 mol/3 L]²
<em>K = 0.0556</em>
4 0
3 years ago
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