The concentration of the new solution is 0.003 M.
<h3>How do we calculate the required concentration?</h3>
Required concentration of the final solution will be calculated by using the below equation as:
M₁V₁ = M₂V₂, where
M₁ & V₁ are the molarity and volume of initial solution.
M₂ & V₂ are the molarity and volume of final solution.
On putting values from the question, we get
M₂ = (0.75)(2) / (500) = 0.003 M
Hence required concentration is 0.003M.
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Answer:
Will up 2NO
Explanation:
The future gas particle will be increased by about 4.2. (estimated) Pressure is absorbed, and by the gas, created heavier.
Au = 79
1s22s22p63s23p63d104s24p64d105s25p64f145d106s1
Or
[Xe] 4f14 5d10 6s1
Depending on how dense something will depend if it floats or sinks.
30 m/hrs (add me on discord if u have it Sipstic++#1460 )