Answer:
3 Cu²⁺(aq) + 2 PO₄³⁻(aq) ⇒ Cu₃(PO₄)₂(s)
Explanation:
Let's consider the molecular equation between aqueous copper(II) chloride and aqueous sodium phosphate.
3 CuCl₂(aq) + 2 Na₃PO₄(aq) ⇒ 6 NaCl(aq) + Cu₃(PO₄)₂(s)
The complete ionic equation includes all the ions and insoluble species.
3 Cu²⁺(aq) + 6 Cl⁻(aq) + 6 Na⁺(aq) + 2 PO₄³⁻(aq) ⇒ 6 Na⁺(aq) + 6 Cl⁻(aq) + Cu₃(PO₄)₂(s)
The net ionic equation includes only the ions that participate in the reaction (not spectator ions) and insoluble species.
3 Cu²⁺(aq) + 2 PO₄³⁻(aq) ⇒ Cu₃(PO₄)₂(s)
POTASSIUM SULFATE hope this helps
Answer:
The temperature remains
Explanation:
The temperature of a boiling substance remains the same because the extra energy is used in phase transition, that is to break the bonds between the molecules that hold them close together in the liquid state. With increased energy the molecules gain enough kinetic energy to overcome inter-molecular forces and change state from liquid to gas
<u>Answer:</u> The total pressure of the container will be 2.00 atm
<u>Explanation:</u>
We are given:
Initial moles of phosphorus pentachloride = 1.00 atm
For the given chemical reaction:
By Stoichiometry of the reaction:
1 mole of 
produces 1 mole of 
and 1 mole of chlorine gas
So, 1.00 atm of will also produce 1.00 atm of and 1.00 atm of chlorine gas when the reaction goes to completion.
Total pressure of the container when the reaction goes to completion = 1.00 + 1.00 = 2.00 atm
Hence, the total pressure of the container will be 2.00 atm
1) Balanced equation
C3H8 + 5O2 -> 3 CO2 + 4 H2O
2) 0.700 L C3H8
Given the pressure and temperature do not change, the molar ratio is equivalent to volume ratio
1molC3H8 / 5 mol O2 => 1 L C3H8 / 5 L O2
0.700 L C3H8 / x L O2 = 1 L C3H8 / 5 L O2 => x = 0.700 L C3H8 * 5 L O2 / 1 L C3H8
x = 3.500 L O2
3) CO2 produced
1 L C3H8 / 3 L CO2 = 0.700 L C3H8 / x L CO2 =>
x = 0.700 L C3H8 * 3 L CO2 / 1 L C3H8 = 2.100 L CO2
4) Water vapor produced
1) 1 L C3H8 / 4 L H2O = 0.700 LC3H8 / x L H2O =>
x = 0.700 L C3H8 * 4 L H20 / 1 L C3H8 = 2.800 L H2O
