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Anestetic [448]
4 years ago
12

If gravity ceased to exist on Earth, what would happen to our life supporting atmosphere ?

Chemistry
1 answer:
melamori03 [73]4 years ago
4 0
C is correct. right now gravity holds the atmosphere so if there is no gravity then no atmospher
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Why does an ion have an electrical charge?
Lelechka [254]
<span>An ion has an electrical charge because it either has more electrons than protons or it has more protons than electrons. Electrons, which are found in the shells of an atom, have a negative charge, while protons, found in the atom's nucleus, have a positive charge.</span>
3 0
4 years ago
What 3 things will you do to dissolve a solid (salt) faster in a liquid (water)
Dmitriy789 [7]

Answer:

There are three ways to make solids dissolve faster: Break the solute into smaller pieces. Stir the mixture. * Heat the mixture.

Explanation:

Substances can dissolve in water three ways—by dissociation, dispersion, and ionization.

6 0
3 years ago
Physical properties of toothpaste
Serggg [28]
Here are a few
 Its colour
Its texture
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4 0
4 years ago
What is the ph of 0.450 m al(no3)3 [ka for al3+(aq) = 1.00x10-5]? express your answer to two decimal places?
White raven [17]

Answer : The pH of the solution is, 2.67

Explanation :

The equilibrium chemical reaction is:

                           Al^{3+}+H_2O\rightarrow Al(OH)^{2+}+H^+

Initial conc.       0.450                   0               0

At eqm.           (0.450-x)                 x               x

As we are given:

K_a=1.00\times 10^{-5}

The expression for equilibrium constant is:

K_a=\frac{(x)\times (x)}{(0.450-x)}

Now put all the given values in this expression, we get:

1.00\times 10^{-5}=\frac{(x)\times (x)}{(0.450-x)}

x=0.00212M

The concentration of H^+ = x = 0.00212 M

Now we have to calculate the pH of solution.

pH=-\log [H^+]

pH=-\log (0.00212)

pH=2.67

Therefore, the pH of the solution is, 2.67

8 0
4 years ago
Solid sodium metal reacts violently with water, producing heat, hydrogen gas, and sodium hydroxide. How many molecules of hydrog
asambeis [7]

Answer:

4.6 × 10²³ molecules:

Step-by-step solution

You will need a balanced equation with masses, moles, and molar masses, so let's gather the information in one place:

M_r:  22.99

          2Na + 2H₂O ⟶ 2NaOH + H₂

m/g:    35

1. Calculate the <em>moles of Na </em>

Moles of Na = 35 g Na × (1 mol Na/22.99 g Na)

Moles of Na = 1.52 mol Na

2. Calculate the <em>moles of H₂ </em>

Moles of H₂ = 1.52 mol Na × (1 mol H₂/2 mol Na)

Moles of H₂= 0.761 mol H₂

3. Calculate the molecules of H₂

6.022 × 10²³ molecules H₂ = 1 mol H₂

                Molecules of H₂ = 0.761 × (6.022 × 10²³ /1)

                Molecules of H₂ = 4.6 × 10²³ molecules H₂

The reaction forms 4.6 × 10²³ molecules of H₂.

5 0
3 years ago
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