The molecular formula would be Li2CO3
Answer:
An object will remain at rest, an object will have a mass and force of accelerations, and for every action there is an equal and opposite reaction.
Explanation:
The answer is 31.5g. See solution below
SO3 + H2O => H2SO4
Theoretical moles of SO3 : H2O = 1 : 1
Moles of SO3 = mass/molar mass of SO3
= 25.7/80.064 = 0.3210 mol
Mass of H2O = volume x density
= 13.9 x 1.00 = 13.9 g
Moles of H2O = mass/molar mass of H2O
= 13.9/18.02 = 0.7714 mol
Experimentall moles of SO3 : H2O = 0.3210 : 0.7714
= 0.416 : 1 = 1 : 2.40
Since H2O is in excess, SO3 is the limiting reactant
Moles of H2SO4 = Moles of SO3 = 0.3210 mol
Mass of H2SO4 = moles x molar mass of H2SO4
= 0.3210 x 98.08
= 31.5 g
I hope this helps!
Answer: Chemical energy
Explanation: In this case plants convert light energy (1) into chemical energy, (in molecular bonds), through a process known as photosynthesis. Most of this energy is stored in compounds called carbohydrates. The plants convert a tiny amount of the light they receive into food energy.
Answer : The concentration of ![[Fe(SCN)]^{2+}](https://tex.z-dn.net/?f=%5BFe%28SCN%29%5D%5E%7B2%2B%7D)
is, 
Explanation :
When we assume this reaction is driven to completion because of the large excess of one ion then we are assuming limiting reagent is 
and 
is excess reagent.
First we have to calculate the moles of KSCN.
Moles of KSCN = Moles of 
= Moles of = 
Now we have to calculate the concentration of
![\text{Concentration of }[Fe(SCN)]^{2+}=\frac{\text{Moles of }[Fe(SCN)]^{2+}}{\text{Volume of solution}}](https://tex.z-dn.net/?f=%5Ctext%7BConcentration%20of%20%7D%5BFe%28SCN%29%5D%5E%7B2%2B%7D%3D%5Cfrac%7B%5Ctext%7BMoles%20of%20%7D%5BFe%28SCN%29%5D%5E%7B2%2B%7D%7D%7B%5Ctext%7BVolume%20of%20solution%7D%7D)
Total volume of solution = (6.00 + 5.00 + 14.00) = 25.00 mL = 0.025 L
![\text{Concentration of }[Fe(SCN)]^{2+}=\frac{1.08\times 10^{-5}mol}{0.025L}=4.32\times 10^{-4}M](https://tex.z-dn.net/?f=%5Ctext%7BConcentration%20of%20%7D%5BFe%28SCN%29%5D%5E%7B2%2B%7D%3D%5Cfrac%7B1.08%5Ctimes%2010%5E%7B-5%7Dmol%7D%7B0.025L%7D%3D4.32%5Ctimes%2010%5E%7B-4%7DM)
Thus, the concentration of is,
