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Travka [436]
3 years ago
11

For both resonance curves and Fourier spectra, amplitude is plotted vs frequency, but these two types of plots are not the same.

Describe how they are different.
Physics
1 answer:
andrey2020 [161]3 years ago
7 0

Answer:

he peaks are the natural frequencies that coincide with the excitation frequencies and in the second case they are the natural frequencies that make up the wave.

Explanation:

In a resonance experiment, the amplitude of the system is plotted as a function of the frequency, finding maximums for the values ​​where some natural frequency of the system coincides with the excitation frequency.

In a Fourier transform spectrum, the amplitude of the frequencies present is the signal, whereby each peak corresponds to a natural frequency of the system.

From this explanation we can see that in the first case the peaks are the natural frequencies that coincide with the excitation frequencies and in the second case they are the natural frequencies that make up the wave.

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Tems11 [23]

Answer:

The thickness of the foil is 0.017 mm.

Explanation:

Given that,

Weight = 7.5 oz = 212.6175 gm

Density = 2.70 g/cm³

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We need to calculate the thickness of the foil

Using formula of density

\rho=\dfrac{m}{V}

\rho=\dfrac{m}{A\times t}

t=\dfrac{m}{A\times \rho}

Where, A = area

t = thickness

m = mass

Put the value into the formula

t=\dfrac{212.6175}{46451.52\times2.70}

t=0.00170\ cm

t=0.017\ mm

Hence, The thickness of the foil is 0.017 mm.

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Explanation:

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7 0
3 years ago
If you start with two sinusoidal waves of the same amplitude traveling in phase on a string and then somehow phase-shift one of
andrew11 [14]

Explanation:

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Answer:

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Explanation:

I think is D

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