All categories

3 years ago

A megamole of titanium contains __________ moles of titanium.

2 answers:

8 0

Answer is: 1 megamole is equal to 1000000 (one million) mole or 10⁶ moles.
The SI base unit for amount of substance is the mole. The SI prefix "mega" represents a factor of 10⁶, or in exponential notation, 1E6.
The mole is the amount of substance of a system which contains as many elementary entities as there are atoms in 12 grams of carbon C-12.

vlada-n [284]3 years ago

7 0

Answer : A megamole of titanium contains 1000000 moles of titanium.

Explanation :

As we are given:

Number of moles of titanium is 1 megamole.

The conversion used from megamole to mole is:

1 megamole = 1000000 mole

or,

1 megamole = $10^6$ mole

Hence, 1 megamole of titanium contains 1000000 moles of titanium.

You might be interested in

C10H22 + O2 -- CO2 + H2O balance

Tasya [4]

Answer:

1,31÷2 =10,11

Explanation:

c10h22+31÷2o2=10co2+11h2o

5 0

3 years ago

Question 2: Which of the following is NOT true about streams?

mafiozo [28]

Answer:

q 3 c q 2 d

Explanation:

8 0

3 years ago

Why does the TLC tank need to be covered?

photoshop1234 [79]

Answer:

The reason for covering the container is to make sure that the atmosphere in the beaker is saturated with solvent vapour. Saturating the atmosphere in the beaker with vapour stops the solvent from evaporating as it rises up the paper.

5 0

3 years ago

Read 2 more answers

Why is it NOT possible for ONE particle (atom/ion/molecule) to be classified as a particular phase, or state, of matter?

Agata [3.3K]

Answer:

because I said and I'm the boss

6 0

3 years ago

A sample of nitrogen gas occupies a volume of 2.55 L when it is at 755 mm Hg and 23 degrees Celsius. Use this information to det

ivolga24 [154]

Answer: The number of moles of nitrogen gas are 0.1043 moles and the pressure when volume and temperature has changed is 461.6 mmHg

Explanation:

To calculate the amount of nitrogen gas, we use the equation given by ideal gas which follows:

$PV=nRT$

where,

P = pressure of the gas = 755 mmHg

V = Volume of the gas = 2.55 L

T = Temperature of the gas = $23^oC=[23+273]K=296K$

R = Gas constant = $62.364\text{ L.mmHg }mol^{-1}K^{-1}$

n = number of moles of nitrogen gas = ?

Putting values in above equation, we get:

$755mmHg\times 2.55L=n\times 62.364\text{ L.mmHg }mol^{-1}K^{-1}\times 296K\\\\n=\frac{755\times 2.55}{62.364\times 296}=0.1043mol$

To calculate the pressure when temperature and volume has changed, we use the equation given by combined gas law.

The equation follows:

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1,V_1\text{ and }T_1$ are the initial pressure, volume and temperature of the gas

$P_2,V_2\text{ and }T_2$ are the final pressure, volume and temperature of the gas

We are given:

$P_1=755mmHg\\V_1=2.55mL\\T_1=23^oC=[23+273]K=296K\\P_2=?\\V_2=4.10L\\T_2=18^oC=[18+273]K=291K$

Putting values in above equation, we get:

$\frac{755mmHg\times 2.55L}{296K}=\frac{P_2\times 4.10L}{291K}\\\\P_2=\frac{755\times 2.55\times 291}{4.10\times 296}=461.6mmHg$

Hence, the number of moles of nitrogen gas are 0.1043 moles and the pressure when volume and temperature has changed is 461.6 mmHg

6 0

3 years ago

Read 2 more answers