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xeze [42]
3 years ago
11

Evaluate the carbon dioxide molecule. Explain how to determine if double or triple bonds exist in the molecule.

Chemistry
1 answer:
S_A_V [24]3 years ago
4 0

Answer:

It contain double Bond.

Explanation:

To determine weather the bond is double or triple simply check the electron involved in mutual sharing of an electron if 2 electron takes parts it said to be double or if 3 it said to be triple.

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Which bent shape has more repulsion and a smaller bond angle?<br> bent 6A<br> bent 5A
Step2247 [10]
Bent 6A is the answer
8 0
3 years ago
Calculate the atomic mass of Carbon if the two common isotopes of carbon have masses of
Mars2501 [29]

Answer:

Average atomic mass of carbon = 12.01 amu.

Explanation:

Given data:

Abundance of C¹² = 98.89%

Abundance of C¹³ = 1.11%

Atomic mass of C¹² = 12.000 amu

Atomic mass of C¹³ = 13.003 amu

Average atomic mass = ?

Solution:

Average atomic mass of carbon = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass)  / 100

Average atomic mass of carbon = (12.000×98.89)+(13.003×1.11) /100

Average atomic mass of carbon=  1186.68 + 14.43333 / 100

Average atomic mass of carbon = 1201.11333 / 100

Average atomic mass of carbon = 12.01 amu.

5 0
3 years ago
What is the mass, in grams, of 28.58 mL of acetone?
Vedmedyk [2.9K]
<span>If you look up the density of Acetone (Propanone in IUPAC names) you will find it is 0.7925g/cm3. This is the same as 0.7925g/ml. 

You can calculate mass using the equation:- mass = density x volume 
In your example mass = 0.7925 x 28.40 = 22.51g</span><span>
I think That's right. Hope this helps!!! Good luck!</span>
7 0
3 years ago
Read 2 more answers
Abhfguojgedfhoobdssghjbhjjbjkjjk<br><br><br> friends ?
Sholpan [36]

Answer:

yessss what's ur snapp?

6 0
2 years ago
The frequency of an x-ray wave is 3.0 x 1012MHz. Its wave speed is 3.0x 108m/s. Calculate the wavelength of the x-ray wave below
jasenka [17]

Answer: The wavelength of the x-ray wave is 10^{-10}m

Explanation:

To calculate the wavelength of light, we use the equation:

\lambda=\frac{c}{\nu}

where,

\lambda = wavelength of the light  = ?

c = speed of x-ray= 3.0\times 10^8m/s

\nu = frequency of x-ray = 3.0\times 10^{12}MHz=3.0\times 10^{18}Hz= 3.0\times 10^{18}s^{-1}     (1Hz=1s^{-1})

Putting in the values:

\lambda=\frac{3.0\times 10^8m/s}{3.0\times 10^{18}s^{-1}}=10^{-10}m

Thus the wavelength of the x-ray wave is 10^{-10}m

5 0
3 years ago
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