From the equation;
a= -1÷2gT2
a= -5×3(3)
a= -45m/s
it will drop about -45m/s2.
The best answer between the two options would be the second choice B) FALSE.
Answer:
Explanation:
Given that,
Kinetic energy of an automobile is 2300J
K.E = 2300J
The formula for kinetic energy is
K.E = ½mv²
So, if the speed of the automobile is increased by 6, what is the kinetic energy
Now v' = 6v.
The mass of the automobile is constant.
Therefore, the kinetic energy is
K.E' = ½mv'²
Where v' = 6v
K.E' = ½m(6v)²
K.E' = ½m × 36v²
K.E' = 36 × ½mv²
Where, from above ½mv² = 2300J
Then,
K.E' = 36 × 2300 = 82,800J
The kinetic energy of the automobile when it increase it's speed is 82,800J
Answer:
B) protons and neutrons.
Explanation:
The protons and neutrons are located in the nucleus of the atom and represent most of the 'mass' of the atom, that's their count that determine the 'mass' of an atom (like 12 for Carbon).
The electrons rotate around the nucleus and have a negligible mass.
