A marble rolls off a tabletop 1.15 m high and hits the floor at a point 4 m away from the edge of the table in the horizontal direction,
- t= 0.45 seconds.
- V=2.22m/s
- VT=4.95 m/s
This is further explained below.
<h3>What is its speed when it hits the floor...?</h3>
Generally, the equation for motion is mathematically given as
S= ut + 0.5at²
Therefore
y = Voy t + 0.5gt^2
1 = 0.5x 98 x 6²
1=4.9t^2

t= 0.45 seconds.
b) Horizontal motions are uniform.
V=Horizontal displacement/time
V=1/0.45
V=2.22m/s
C)
Vx: 2.22 m/s At bottom,
Vy² = Voy² + 2as
Vy² = 2x95x1
Vy² = 19.6
Total velocity

VT=4.95 m/s
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Since acceleration is constant, we can use the formula
v² - u² = 2a ∆x
where v = final velocity, u = initial velocity, a = acceleration, and ∆x = displacement. Then
0² - (20.0 m/s)² = 2 (-4.20 m/s²) ∆x
⇒ ∆x = (20.0 m/s)² / (8.40 m/s²) ≈ 47.6 m
The mechanical energy of an object is the sum of its potential and kinetic energy.
Because the ball is on the ground, its potential energy is 0.
Its kinetic energy is given by:
K.E = 1/2 mv²
K.E = 1/2 x 1 x 2²
K.E = 2 J
Mechanical energy = 2 + 0
Mechanical energy = 2 J
The answer is B.
Answer:
The fraction of the total energy goes into kinetic energy of proton is 
Explanation:
Given:
Mass of proton 
Mass of electron
kg
Here neutron at rest decays into proton and electron
⇄ 
Where
energy released
The
value of this reaction is given by

Where
kinetic energy of reaction
Here we need to find fraction of the total energy released goes into the kinetic energy of the proton




Therefore, the fraction of the total energy goes into kinetic energy of proton is 