Answer
diameter of parking lot = 18 in
flowrate = 10 ft³/s
pressure drop = 100 ft
using general equation
taking f = 0.0185
at Z₁ = Z₂
ΔP = 0.266 psi
b) when flow is uphill z₂-z₁ = 2
c) When flow is downhill z₂-z₁ = -2
Answer:
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Explanation:
true
Answer:
w = 0.626 rad / s, v = 3.13 m/s
Explanation:
For this exercise let's use Newton's second law
F = m a
Where the force is a friction force and the acceleration is centripetal,
a = v² / r = w² r
The formula for friction force
fr = μ N
In a free body diagram
N- W = 0
W = N
The frictiμon outside goes from zero to the maximum value, let's calculate the speed for the maximum value of the friction force, replace
μ m g = m w² r
w = √ μ g / r
Let's calculate
w = √(0.2 9.8 / 5)
w = 0.626 rad / s
angular and linear velocity are related
v = w r
v = 0.626 5
v = 3.13 m/s
