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Y_Kistochka [10]
2 years ago
12

hen approaching a curve, it is best to: A. Search for possible collision traps and escape paths B. Stay close to the centerline

if there is oncoming traffic C. Squeeze the clutch lever to slow down D. Shift to a higher gear
Physics
1 answer:
WINSTONCH [101]2 years ago
8 0

Squeezing the clutch lever to slow down is best to be done when approaching a curve and is denoted as option C.

<h3>What is Clutch?</h3>

This is a mechanical device which used in the engagement and disengagement of transmission system in a vehicle.

Slowing down will give the driver more time to maneuver the curves so as to prevent accident. This is why it is imperative to squeeze the clutch in such road condition.

Read more about Clutch here brainly.com/question/14318041

#SPJ1

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Two point charges of -7uC and 4uC are a distance of 20
aivan3 [116]

Answer:

Approximately 0.979 J.

Explanation:

Assume that the two charges are in vacuum. Apply the coulomb's law to find their initial and final electrical potential energy \mathrm{EPE}.

\displaystyle \mathrm{EPE} = \frac{k \cdot q_1 \cdot q_2}{r},

where

  • The coulomb's constant k = 8.99\times 10^{9}\; \rm N\cdot m^{2} \cdot C^{-2},
  • q_1 and q_2 are the sizes of the two charges, and
  • r is the separation of (the center of) the two charges.

Note that there's no negative sign before the fraction.

Make sure that all values are in SI units:

  • q_1 = -7\rm \;\mu C = -7\times 10^{-6}\; C;
  • q_2 = 4\rm \;\mu C = 4\times 10^{-6}\; C;
  • Initial separation: \rm 20\; cm = 0.20\; cm;
  • Final separation: \rm 90\; cm = 0.90\; cm.

Apply Coulomb's law:

Initial potential energy:

\begin{aligned} \frac{k \cdot q_1 \cdot q_2}{r} &= \frac{8.99\times 10^{9}\times (-7\times 10^{-6})\times 4\times 10^{-6}}{0.20}\\&= \rm -1.2586\; J\end{aligned}.

Final potential energy:

\begin{aligned} \frac{k \cdot q_1 \cdot q_2}{r} &= \frac{8.99\times 10^{9}\times (-7\times 10^{-6})\times 4\times 10^{-6}}{0.90}\\&= \rm -0.279689\; J\end{aligned}.

The final potential energy is less negative than the initial one. In other words, the two particles gain energy in this process. The energy difference (final minus initial) will be equal to the work required to move them at a constant speed.

\begin{aligned}\text{Work required} &= \text{Final EPE} - \text{Initial EPE}\\&= \rm  -0.279689\; J - (-1.2586\; J)\\&\approx 0.979\; J\end{aligned}.

8 0
3 years ago
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Convert 1 x 10-3 nm to m. given: 1 m = 1,000,000,000 nm
vampirchik [111]

Answer:

l m = 1000000000 nm

? = 0.001

= 0

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3 years ago
What kind of energy is stored when you squeeze a mattress?
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Elastic Energy is stored in it.
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What happens in terms of energy when a moving car hit a parked car causing the park card to move?
olga_2 [115]
Its like newtons 3rd law that once in motion a outer force has to stop it
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What equations would you use to find force?
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Answer:

F = m x a

Explanation:

F = force

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