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olchik [2.2K]
2 years ago
14

Block 1 (mass 2.00 kg) is moving rightward at 10.0 m/s and block 2 (mass 5.00 kg) is moving rightward at 3.00 m/s. The surface i

s frictionless, and a spring with a spring constant of 1120 N/m is fixed to block 2. When the blocks collide, the compression ofthe spring is maximum at the instant the blocks have the same velocity. (a) Find the maximum compression.(b) Find the final velocities of the two blocks.
Physics
1 answer:
DaniilM [7]2 years ago
5 0

Answer:

a) 0.25m

b) 5 m/s

Explanation:

When the spring is compressed both boxes are moving with the same velocity, so applying the principle of linear momentum conservation:

m1*v_{o1}+m2*v_{o2}=(m1+m2)*v\\v=5m/s

Now applying the principle of energy conservation:

K1+K2+U_{g1}-U_e=Kf+U_{g2}\\K1+0-U_e=K2+0\\U_e=K1+K2-kf\\\frac{1}{2}*k*x^2+=\frac{1}{2}*m1*v1^2+\frac{1}{2}*m1*v1^2-\frac{1}{2}*(m1+m2)*v^2\\\\x=\sqrt{\frac{2.00kg*(10m/s)^2+5.00kg*(3.00m/s)^2-7.00kg*(5m/s)^2}{1120N/m}}\\x=0.25m

We got that the maximum compression is 0.25m.

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