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Crank
2 years ago
5

Set up the math problem. But don’t do any of it. Just leave your answer as a math expression. Also be sure you’re answering clue

s all the correct the units symbols.

Chemistry
1 answer:
natta225 [31]2 years ago
3 0

Answer:

Length = 681 grams / (44.5 grams / kilometers) = (681 / 44.5) kilometers

Explanation:

The diameter is there to throw us off, so ignore that. There is 681 grams of wire, and since there is 44.5 grams of copper <em>per</em> km of wire, and we want to know how many kilometers of wire makes 681 grams, the equation would be X*44.5 = 681, or X = 681/44.5


Also quora's censoring system is terrible i can't even say kilometers by adding the letter s after "km"

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If 6.4 miles of Fe react with excess O2, how many miles of Fe2O3 can be formed? 4 Fe + 3 O2 -&gt; 2 Fe2O3
Yuri [45]
I'm assuming that by "miles" you mean moles.

If O2 is the excess reactant, that means Fe is the limiting reactant. That means that the amount of product being formed depends on the amount of Fe reactant present. To calculate the moles of Fe2O3 formed, start with the given 6.4 moles of Fe and use the mole to mole ratio given by the reaction as shown below:

6.4 mol Fe x \frac{2 mol Fe2O3}{4 mol Fe} = 3.2 mol Fe2O3
6 0
3 years ago
Calculate the ionic strength of a solution of iron (iii) carbonate, fe2(co3)3 of concentration 0.020 mol dm
Ede4ka [16]
E=b(x^3)×co3x{fe2}+13^3
6 0
3 years ago
A solution is made by dissolving
nikklg [1K]

Answer:

THE MOLARITY IS 2.22 MOL/DM3

Explanation:

The solution formed was as a result of dissolving 37.5 g of Na2S in 217 g of water

Relative molecular mass of Na2S = ( 23* 2 + 32) = 78 g/mol

Molarity in g/dm3 is the amount of the substance dissolved in 1000 g or 1 L of the solvent. So we have;

37.5 g of Na2S = 217 g of water

( 37.5 * 1000 / 217 ) g = 1000 g of water

So, 172.81 g/dm3 of the solution

So therefore, molarity in mol/dm3 = mol in g/dm3 / molar mass

Molarity = 172.81 g/dm3 / 78 g/mol

Molarity = 2.22 mol/dm3

The molarity of the solution is 2.22 mol/dm3

4 0
3 years ago
The concentration of CI ion in a sample of H,0 is 15.0 ppm. What mass of CI ion is present in 240.0 mL of H,0, which has a densi
Doss [256]

Answer:

Mass of solute = 0.0036 g

Explanation:

Given data:

Concentration of Cl⁻ = 15.0 ppm

Volume of water = 240 mL

Mass of Cl⁻ present = ?

Solution:

1 mL = 1 g

240 mL = 240 g

Formula:

ppm = mass of solute / mass of sample ×1,000,000

by putting values,

15.0 ppm = (mass of solute / 240 g) ×1,000,000

Mass of solute = 15.0 ppm ×  240 g / 1,000,000

Mass of solute = 0.0036 g

8 0
2 years ago
Convert eachh into scientific notation
mixer [17]

Answer:

0.00580 →

3000 →

0.000908 →

200. →

Explanation:

yay

7 0
3 years ago
Read 2 more answers
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