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natka813 [3]
3 years ago
14

Suppose 15.00 mL of 3.0 x 10^{-6} M Fe(NO3)3 is added to 15.00 mL of 3.0 x 10^ –4 M KIO3. Will a precipitate form? Explain why.

For Fe(IO3)3, Ksp = 1.0 x 10–14.
Chemistry
1 answer:
matrenka [14]3 years ago
5 0
It is 30292
2 \times 2 \sqrt[ > ]{?}
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Yes, it ca,n <span>if it has been cooled to very low temperatures</span>
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2.643 grams of potassium butanoate (KCH3(CH2)2CO2 ) is fully dissolved in 50.00 mL of water, which is carefully transferred to a
lara [203]

Answer:

The pH of the solution is 4.69

Explanation:

Given that,

Mass of potassium = 2.643 grams

Weight of water = 50.00 mL

Weight of HCl=100.00 ml

Mole = 0.120 M

We know that,

KCH_{3}(CH_{2})_{2}CO_{2} is a basic salt.

Let's write it as KY.

The acid HCH_{3}(CH_{2}CO_{2}) would become HY.

We need to calculate the moles of KY

Using formula of moles

moles\ of\ KY=\dfrac{m}{M}\times1000

moles\ of\ KY=\dfrac{2.643}{126}\times1000

moles\ of\ KY=20.97\ m\ mole

The reaction is

KY+HCl\Rightarrow HY+ KCl

The number of moles of KY is 20.98 m

initial moles = 20.98

Final moles m=20.98-0.120\times100= 8.98

We need to calculate the value of pKa(HY)

Using formula for pKa(HY)

pKa_{HY}=-log Ka

pKa_{HY}=-log(1.5\times10^{-5})

pKa_{HY}=4.82

We need to calculate the pH of the solution

Using formula of pH

pH=pKa+log(\dfrac{[KY]}{[KH]})

Put the value into the formula

pH=4.82+log(\dfrac{8.98}{12})

pH=4,69

Hence, The pH of the solution is 4.69

7 0
3 years ago
Part 1. A chemist reacted 15.0 liters of F2 gas with NaCl in the laboratory to form Cl2 and NaF. Use the ideal gas law equation
xeze [42]

Answer:

113 g NaCl

Explanation:

The Ideal Gas Law equation is:

PV = nRT

In this equation,

    > P = pressure (atm)

    > V = volume (L)

    > n = number of moles

    > R = 8.314 (constant)

    > T = temperature (K)

The given values all have to due with the conditions fo F₂. You have been given values for all of the variables but moles F₂. Therefore, to find moles F₂, plug each of the values into the Ideal Gas Law equation and simplify.

(1.50 atm)(15.0 L) = n(8.314)(280. K)

2250 = n(2327.92)

0.967 moles F₂ = n

Using the Ideal Gas Law, we determined that the moles of F₂ is 0.967 moles. Now, to find the mass of NaCl that can react with F₂, you need to (1) convert moles F₂ to moles NaCl (via the mole-to-mole ratio using the reaction coefficients) and then (2) convert moles NaCl to grams NaCl (via molar mass from periodic table). It is important to arrange the ratios/conversions in a way that allows for the cancellation of units (the desired unit should be in the numerator).

1 F₂ + 2 NaCl ---> Cl₂ + 2NaF

Molar Mass (NaCl): 22.99 g/mol + 35.45 g/mol

Molar Mass (NaCl): 58.44 g/mol

0.967 moles F₂        2 moles NaCl             58.44 g
----------------------  x  -----------------------  x  -----------------------  =  113 g NaCl
                                     1 mole F₂              1 mole NaCl

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2 years ago
Do metals donate or accept electrons? what do they become after they donate/accept electrons?
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Which formula represents a hydrocarbon with a double covalent bond?
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Answer:

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