Isotopes are forms of the same elements which contain equal number of protons but different number of nucleus in their nuclei, thus the differ in relative atomic mass but they have same chemical properties. The mass number is the summation of number of proton and number of neutron of an atom. If the mass number is known, then one need to know the number of proton in the atom in order to calculate for the number of neutron.
Answer:
[Cl⁻] = 0.016M
Explanation:
First of all, we determine the reaction:
Pb(NO₃)₂ (aq) + MgCl₂ (aq) → PbCl₂ (s) ↓ + Mg(NO₃)₂(aq)
This is a solubility equilibrium, where you have a precipitate formed, lead(II) chloride. This salt can be dissociated as:
PbCl₂(s) ⇄ Pb²⁺ (aq) + 2Cl⁻ (aq) Kps
Initial x
React s
Eq x - s s 2s
As this is an equilibrium, the Kps works as the constant (Solubility product):
Kps = s . (2s)²
Kps = 4s³ = 1.7ₓ10⁻⁵
4s³ = 1.7ₓ10⁻⁵
s = ∛(1.7ₓ10⁻⁵ . 1/4)
s = 0.016 M
Answer:
Mohamed Osama El Sayed El kordy
Answer : The value of
for the final reaction is, 184.09
Explanation :
The equilibrium reactions in aqueous solution are :
(1)
![K_{c_1}=4.5\times 10^{-4}](https://tex.z-dn.net/?f=K_%7Bc_1%7D%3D4.5%5Ctimes%2010%5E%7B-4%7D)
(2)
![K_{c_2}=1.1\times 10^{-9}](https://tex.z-dn.net/?f=K_%7Bc_2%7D%3D1.1%5Ctimes%2010%5E%7B-9%7D)
The final equilibrium reaction is :
![K_{c}=?](https://tex.z-dn.net/?f=K_%7Bc%7D%3D%3F)
Now we have to calculate the value of
for the final reaction.
Now equation 1 is multiply by 2 and reverse the equation 2, we get the value of final equilibrium reaction and the expression of final equilibrium constant is:
![K_c=\frac{(K_{c_1})^2}{K_{c_2}}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%28K_%7Bc_1%7D%29%5E2%7D%7BK_%7Bc_2%7D%7D)
Now put all the given values in this expression, we get :
![K_c=\frac{(4.5\times 10^{-4})^2}{1.1\times 10^{-9}}=184.09](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%284.5%5Ctimes%2010%5E%7B-4%7D%29%5E2%7D%7B1.1%5Ctimes%2010%5E%7B-9%7D%7D%3D184.09)
Therefore, the value of
for the final reaction is, 184.09
Alteration of the physical form of a drug outside its label is compounding
It is called compounding according to some sources.