Answer is: the freezing point is 1.63°C and boiling point is 82.01°C.<span>.
1) n(</span><span>nonelectrolyte solute) = 0.656 mol.
</span>m(C₆H₆ - benzene) = 869 g ÷ 1000 g/kg.
m(C₆H₆) = 0.869 kg.<span>
b(solution) = n(</span>nonelectrolyte solute) ÷ m(C₆H₆).<span>
b(solution) = 0.656 mol ÷ 0.869 kg.
b(solution) = 0.754 mol/kg.
2) ΔT = Kf(benzene) · b(solution).
ΔT = 5.12°C/m · 0.754 m.
ΔT = 3.865°C.
Tf = 5.50°C - 3.865°C.
Tf = 1.63°C.
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3) ΔTb = Kb(benzene) · b(solution).
ΔTb = 2.53°C/m · 0.754 m.
ΔTb = 1.91°C.
Tb = 80.1°C + 1.91°C.
Tb = 82.01°C.<span>
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1. electrostatic interactions
<span>3. van de waals interactions </span>
<span>4. hydrogen bonding </span>
Explanation:
The number of orbitals in the sublevels are given below:
Sublevels Orbitals
s 1
p 3
d 5
f 7
a. ls - 1 orbital
b. 5s - 1 orbital
c. 4d - 5 orbitals
d. 4f - 7 orbitals
e. 7s - 1 orbital
f. 3p - 3 orbitals
g. Entire 5th principal energy level : for s, p , f
1 + 3 + 5 + 7 + 9 = 25
h. 6d - 5
The correct answer to your question is B,, make the solute particles smaller.
let me know if you have any further questions
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