Ask question

Ask question

All categories

PSYCHO15rus [73]

3 years ago

15

A 17g sample of H2O2 was decomposed to yield 1g of H2 and 16g of O2 An unknown sample containing only H and O was decomposed to

yeild 2g of H2 and 16 g of O2. The formula for the unknown sample is:

1 answer:

ludmilkaskok [199]3 years ago

5 0

Answer:

Explanation:

Our $H_2O_2$ sample yielded 1g of $H_2$ and 16g of $O_2$ , but our unknown sample yielded 2 times as much $H_2$ for the same amount of $O_2$ .

What does this mean? that the H:O proportion for the unknown sample is twice the H:O proportion for the $H_2O_2$ sample.

What is the H:O proportion for the $H_2O_2$ sample? As we can see from its formula, it's 1:1, therefore the proportion for the unknown formula must be 2:1.

That means, two H atoms for every O atom. We could write that as: $H_2O$ and you should recognize that formula, for it is one of the most common compounds on earth, Water.

You might be interested in

What would be the composition and ph of an ideal buffer prepared from lactic acid (ch3chohco2h), where the hydrogen atom highlig

Mashutka [201]

Answer:

$P_H =2.86$

$c=1.4\times 10^{-4}$

Explanation:

first write the equilibrium equaion ,

$C_3H_6O_3$ ⇄ $C_3H_5O_3^{-} +H^{+}$

assuming degree of dissociation $\alpha$ =1/10;

and initial concentraion of $C_3H_6O_3$ =c;

At equlibrium ;

concentration of $C_3H_6O_3 = c-c\alpha$

$[C_3H_5O_3^{-} ]= c\alpha$

$[H^{+}] = c\alpha$

$K_a = \frac{c\alpha \times c\alpha}{c-c\alpha}$

$\alpha$ is very small so $1-\alpha$ can be neglected

and equation is;

$K_a = {c\alpha \times \alpha}$

$[H^{+}] = c\alpha$ = $\frac{K_a}{\alpha}$

$P_H =- log[H^{+} ]$

$P_H =-logK_a + log\alpha$

$K_a =1.38\times10^{-4}$

$\alpha = \frac{1}{10}$

$P_H= 3.86-1$

$P_H =2.86$

composiion ;

$c=\frac{1}{\alpha} \times [H^{+}]$

$[H^{+}] =antilog(-P_H)$

$[H^{+} ] =0.0014$

$c=0.0014\times \frac{1}{10}$

$c=1.4\times 10^{-4}$

6 0

3 years ago

2 HCl + 1 Zn -> 1 H2 + ZnCl2 what type of reaction is this

Salsk061 [2.6K]

Answer:

Single replacement reaction

Explanation:

3 0

3 years ago

The city is using sand trucks to place on the road during ice conditions which best explians the use of the sand

Stolb23 [73]

The sand provides a rough surface on top of the ice for the cars' tires to grip onto. It provides more friction. Salt melts the ice and often provides more friction (the disadvantage is that it eats concrete!).

6 0

3 years ago

He molecular formula mass of this compound is 180 amu . what are the subscripts in the actual molecular formula?

mezya [45]

I can't actually answer this one if the empirical formula is not given. Luckily, I've found a similar problem from another website. The problem is shown in the picture attached. It shows that the empirical formula is CH₂O. Let's calculate the molar mass of the empirical formula.

Molar mass of E.F = 12 + 2(1) + 16 = 30 g/mol

Then, let's divide this to the molar mass of the molecular formula.
Molar mass of M.F/Molar mass of E.F = 180/30 = 6

Therefore, let's multiply 6 to each subscript in the empirical formula to determine the actual molecular formula.
<em>Actual molecular formula = C₆H₁₂O₆</em>

5 0

3 years ago

Spell out the full name of the compound.

Talja [164]

Answer:

2–methyl–3–propylheptane.

Explanation:

The name of the compound can be obtained as follow:

1. Identify the functional group of the compound.

2. Determine the name of the compound by determining the longest continuous carbon chain.

3. Identify the substituent group attached.

4. Locate the position of the substituent group by giving it the lowest possible count. Where there are two or more different substitutent group attached to the compound, name them alphabetically.

5. Name the compound by combining

the above steps.

Thus, we can name the compound as follow:

1. The compound has only single bond. Therefore, the compound is an alkane.

2. The longest continuous carbon chain is 7. Therefore, the parent name of the compound is heptane.

3. The substitutent groups attached are:

Propyl i.e –C3H7

Methyl i.e –CH3

4. The substituent groups are located at:

Propyl i.e –C3H7 is located at carbon 3.

Methyl i.e –CH3 is located at carbon 2.

5. The name of the compound is:

2–methyl–3–propylheptane.

6 0

2 years ago