Answer:
Enthalpy at outlet=284.44 KJ
Explanation:
![m_1=1 Kg/s,m_2=1.5 Kg/s,m_3=22 Kg/s](https://tex.z-dn.net/?f=m_1%3D1%20Kg%2Fs%2Cm_2%3D1.5%20Kg%2Fs%2Cm_3%3D22%20Kg%2Fs)
![h_1=100 KJ/Kg,h_2=120 KJ/Kg,h_3=500 KJ/Kg](https://tex.z-dn.net/?f=h_1%3D100%20KJ%2FKg%2Ch_2%3D120%20KJ%2FKg%2Ch_3%3D500%20KJ%2FKg)
We need to Find enthalpy of outlet.
Lets take the outlet mass m and outlet enthalpy h.
So from mass conservation
![m_1+m_2+m_3=m](https://tex.z-dn.net/?f=m_1%2Bm_2%2Bm_3%3Dm)
m=1+1.5+2 Kg/s
m=4.5 Kg/s
Now from energy conservation
![m_1h_1+m_2h_2+m_3h_3=mh](https://tex.z-dn.net/?f=m_1h_1%2Bm_2h_2%2Bm_3h_3%3Dmh)
By putting the values
![1\times 100+1.5\times 120+2\times 500=4.5\times h](https://tex.z-dn.net/?f=1%5Ctimes%20100%2B1.5%5Ctimes%20120%2B2%5Ctimes%20500%3D4.5%5Ctimes%20h)
So h=284.44 KJ
Answer:
a) the power consumption of the LEDs is 0.25 watt
b) the LEDs drew 0.0555 Amp current
Explanation:
Given the data in the question;
Three AAA Batteries;
<---- 1000mAh [ + -] 1.5 v ------1000mAh [ + -] 1.5 v --------1000mAh [ + -] 1.5 v------
so V_total = 3 × 1.5 = 4.5V
a) the power consumption of the LEDs
I_battery = 1000 mAh / 18hrs { for 18 hrs}
I_battery = 1/18 Amp { delivery by battery}
so consumption by led = I × V_total
we substitute
⇒ 1/18 × 4.5
P = 0.25 watt
Therefore the power consumption of the LEDs is 0.25 watt
b) How much current do the LEDs draw
I_Draw = I_battery = 1/18 Amp = 0.0555 Amp
Therefore the LEDs drew 0.0555 Amp current
Answer:
Point force (Qp) = 704 kn/m²
Explanation:
Given:
length = 19 m
Width = 0.5 m
fs = 4
Vicinity of the pile = 25
Find:
Point force (Qp)
Computation:
Point force (Qp) = fs²(l+v)
Point force (Qp) = 4²(25+19)
Point force (Qp) = 16(44)
Point force (Qp) = 704 kn/m²
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