Answer:
moment of inertia = 4.662 * 10^6
Explanation:
Given data :
Mass of machine = 400 kg = 400 * 9.81 = 3924 N
length of span = 3.2 m
E = 200 * 10^9 N/m^2
frequency = 9.3 Hz
Wm ( angular frequency ) = 2 = 58.434 rad/secs
also Wm = ------- EQUATION 1
g = 9.81
deflection of simply supported beam
t =
insert the value of t into equation 1
W =
make I the subject of the equation
I ( Moment of inertia about the neutral axis ) =
I = = 4.662 * 10^6
Answer:
The weight should be added to the base of the sign to keep it from tipping is 65.6 lb
Explanation:
Given data:
A sigh weighs 40 pounds
Suported by an 18 in x 18 in square
Force of the wind 13.2 lb
Questions: Will the sign tip over, if yes, how much evelnly distributed weight should be added to the base of the sign to keep it from tipping, W = ?
The sign and the post have a length of 6 ft. You need to calculate the distance from the edge to the middle point:
18/2 = 9 in = 0.75 ft
Force acting in the base (40 lb):
The weight should be added to the base: