Answer:
theoretical fracture strength = 16919.98 MPa
Explanation:
given data
Length (L) = 0.28 mm = 0.28 × 10⁻³ m
radius of curvature (r) = 0.002 mm = 0.002 × 10⁻³ m
Stress (s₀) = 1430 MPa = 1430 × 10⁶ Pa
solution
we get here theoretical fracture strength s that is express as
theoretical fracture strength =
.............................1
put here value and we get
theoretical fracture strength =
theoretical fracture strength =
theoretical fracture strength = 16919.98 MPa
Answer:
8.24μm
Explanation:
The theory of brittle fracture was used to solve this problem.
And if you follow through with the attachment made a the subject of the formula
Such that,
a = 2x(69x10⁹)x0.3/pi(40x10⁶)²
= 4.14x10¹⁰/5.024x10¹⁵
= 8.24x10^-06
= 8.24μm
This is the the maximum length of the surface flaw
Answer:
Detailed solution is attached below in three simple steps the problem is solved.