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3 years ago

11

What energy does a curcuit board run on

2 answers:

Citrus2011 [14]3 years ago

8 0

Answer:

energy from computer

Explanation:

son4ous [18]3 years ago

6 0

a curcuit board is powered by energy from the computers power soarce

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Three methods by which the value of the unknown resistance can be determined

Contact [7]

Answer:

The Meter bridge is the modification of Wheatstone's network used to determine the value of unknown resistance. The meter bridge consists of a thin, uniform, and homogenous conducting wire AC, rectangular wooden board between two thick L shaped metal strips C1 and C2 as shown in the diagram.

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3 years ago

A viscometer may be created by using a pair of closely fitting concentric cylinders and filling the gap between the cylinder wit

kari74 [83]

Answer:

The viscosity of the fluid is 6.05 Pa-s

Explanation:

The viscosity obtained from a rotating type viscometer is given by the equation

$\mu =\frac{3Tt}{2\pi \omega R_o(R_o^3-R_i^3)}$

where

T is the torque applied in the viscometer

't' is the thickness of gap

$\omega$ is the angular speed of rotation

$R_o,R_i$ are the outer and the inner raddi respectively

Since it is given that

$\omega =100rpm=\frac{100\times 2\pi }{60}=10.47rad/sec$

Applying the values in the above relation we get

$\mu =\frac{3\times 0.021\times 0.02\times 10^{-3}}{2\pi \times 10.47\times 37.5\times 10^{-3}(37.52^3-37.5^3)\times 10^{-9}}=6.04Pa-s$

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3 years ago

Which of the following is an example of an observation?

Novay_Z [31]

The monkey is brown!

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3 years ago

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A piston-cylinder assembly contains 2 lb of air at a temperature of 540 degrees R and a pressure of 1 atm. The air is compressed

attashe74 [19]

Answer:

$W=-123.8Btu$

Explanation:

Hello,

In this problem, the piston-cylinder assembly make us state the energy balance as:

$Q-W=\Delta U$

Thus, we must now compute $\Delta U$ in terms of Cv as follows:

$\Delta U=mCv(T_2-T_1)\\\Delta U=2lb*0.173\frac{Btu}{lb*R}*(840R-540R)\\ \Delta U=103.8Btu$

Now, since heat is given off, its sign is negative, thus, the work is computed as:

$W=Q-\Delta U\\W=-20Btu-103.8Btu=-123.8Btu$

This work means that work was done over the system in order to allow the compression.

The suppositions were:

- The change in the internal energy is a function of the temperature.

- Air is an ideal gas.

Best regards.

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4 years ago

Guys I really need a lot of help on some engineering questions due tommorrow. If theres anyway your good at this topic pls comen

Olegator [25]

Answer:

I might be able to help

i took engineering for a year so i might be of help! ill try my best but if not i do apologize

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3 years ago