Answer:
B) 0.32 %
Explanation:
Given that:
Concentration = 1.8 M
Considering the ICE table for the dissociation of acid as:-
The expression for dissociation constant of acid is:
![K_{a}=\frac {\left [ H^{+} \right ]\left [ {CH_3COO}^- \right ]}{[CH_3COOH]}](https://tex.z-dn.net/?f=K_%7Ba%7D%3D%5Cfrac%20%7B%5Cleft%20%5B%20H%5E%7B%2B%7D%20%5Cright%20%5D%5Cleft%20%5B%20%7BCH_3COO%7D%5E-%20%5Cright%20%5D%7D%7B%5BCH_3COOH%5D%7D)
Solving for x, we get:
<u>x = 0.00568 M</u>
Percentage ionization = 
<u>Option B is correct.</u>
2Al₂O₃ → 4Al + 3O₂
the mole ratio is 4:3
for every 4 Al, there must be 3 O₂ in order to make 2Al₂O₃
hope this helped at all
Answer:
B. s, p, d, f
Explanation:
These things are often referred to as suborbitals and you normally have s,p,d,f.
S has 1 two orbitals
P has 3 orbitals
D has 5 orbitals
F has 7 orbitals
and each orbital can house 2 electrons
Explanation:
1) Amphoteric substances can react both like an acid or a base depending if they are in presence of a base or an acid.
Zinc hydroxide (Zn(OH)2):
In acid: 
In base: ![Zn(OH)_2 + 2 NaOH \longrightarrow Na_2[Zn(OH)_4]](https://tex.z-dn.net/?f=Zn%28OH%29_2%20%2B%202%20NaOH%20%5Clongrightarrow%20Na_2%5BZn%28OH%29_4%5D)
Aluminium hydroxide (Al(OH)3)
In acid: 
In base: ![Al(OH)_3 + NaOH \longrightarrow Na[Al(OH)_4]](https://tex.z-dn.net/?f=Al%28OH%29_3%20%2B%20NaOH%20%5Clongrightarrow%20Na%5BAl%28OH%29_4%5D)
2) Reactions
a) 
b) 
According to the U.S. Geological Survey, most of that three percent is inaccessible. Over 68 percent of the fresh water on Earth is found in icecaps and glaciers, and just over 30 percent is found in ground water. Only about 0.3 percent of our fresh water is found in the surface water of lakes, rivers, and swamps.
