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trapecia [35]
3 years ago
8

Which response includes all the following processes that are accompanied by an increase in entropy? 1) 2SO 2(g) + O 2(g) → SO 3(

g) 2) H 2O(l) → H 2O(s) 3) Br 2(l) → Br 2(g) 4) H 2O 2(l) → H 2O(l) + 1/ 2O 2(g)
Chemistry
1 answer:
Mashutka [201]3 years ago
4 0

Answer: Reaction (1) , (3) and (4) are accompanied by an increase in entropy.

Explanation:

Entropy is the measure of randomness or disorder of a system. If a system moves from  an ordered arrangement to a disordered arrangement, the entropy is said to decrease and vice versa.

(1) 2SO_2(g)+O_2(g)\rightarrow SO_3(g)

3 moles of reactant are changing to 1 mole of product , thus the randomness is increasing. Thus the entropy also increases.

2) H_2O(l)\rightarrow H_2O(s)

1 mole of Liquid reactant is changing to 1 mole of solid product , thus the randomness is decreasing. Thus the entropy also decreases.

3) Br_2(l)\rightarrow Br_2(g)

1 mole of Liquid reactant is changing to 1 mole of gaseous product , thus the randomness is increasing. Thus the entropy also increases.

4)  H_2O_2(l)\rightarrow H_2O(l)+\frac{1}{2}O_2(g)

1 mole of Liquid reactant is changing to half mole of gaseous product and 1 mole of liquid product, thus the randomness is increasing. Thus the entropy also increases.

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miss Akunina [59]

Answer: cause oxegeon is harmful then helium

Explanation:

3 0
4 years ago
How many molecules in 2.50 moles of NH; ?
Alexus [3.1K]
To find out how many molecules you have, you need to multiply the number of moles with Avogadros constant: 2.50 * 6.022 * 10²³ = 1.5055 * 10^24.
6 0
3 years ago
50.0 mL of a solution of HCl is combined with 100.0 mL of 1.05M NaOH in a calorimeter. The reaction mixture is initially at 22.4
VikaD [51]

Answer:

2.1 M is the molarity of the HCl solution.

Explanation:

HCl+NaOH\rightarrow H_2O+NaCl

Molarity of HCl solution = M_1=?

Volume of HCl solution = V_1=50.0mL

Ionizable hydrogen ions in HCl = n_1=1

Molarity of NaOH solution = M_2=1.05 M

Volume of NaOH solution = V_2=100.0 mL

Ionizable hydroxide ions in NaOH = n_2=1

n_1M_1V_1=n_2M_2V_2 (neutralization )

M_1=\frac{M_2V_2}{V_1}=\frac{1.05M\times 100.0 mL}{50.0 mL}

M_1=2.1 M

2.1 M is the molarity of the HCl solution.

3 0
3 years ago
How do people who supply their own water generally obtain it? (Site 1)
ale4655 [162]
They usually get it from an old well they dug up and have a pump and strainer that go to their house.
6 0
3 years ago
Ammonia, nh3, is a weak base with a kb = 1.8 x 10-5. in a 0.8m solution of ammonia, which has a higher concentration: ammonia (n
insens350 [35]
Answer is: concentration ammonia is higher than concentration of ammonium ion.
Chemical reaction of ammonia in water: NH₃ + H₂O → NH₄⁺ + OH⁻.
Kb(NH₃) = 1,8·10⁻⁵.
c₀(NH₃) = 0,8 mol/L.
c(NH₄⁺) = c(OH⁻) = x.
c(NH₃) = 0,8 mol/L - x.
Kb = c(NH₄⁺) · c(OH⁻) / c(NH₃).
0,000018 = x² /  0,8 mol/L - x.
solve quadratic equation: x = c(NH₄⁺) = 3,79·10⁻³ mol/L.
7 0
3 years ago
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