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olasank [31]
3 years ago
11

Suppose that at one stage in the reaction, 26.0 mol SO , 2 83.0 mol O2, and 17.0 mol SO3 are present in the reaction vessel at a

total pressure of 0.950 atm. Calculate the mole fraction of SO3 and its partial pressure.
Chemistry
1 answer:
prohojiy [21]3 years ago
4 0

Answer:

- Mole fraction of SO₃ : 0.135

- Partial pressure SO₃ = 0.128 atm

Explanation:

Let's find out the mole fraction to know, what we were asked.

Mole fraction = Moles of a gas / Total moles

Mole fraction can also corresponds to Pressures, like this:

Mole fraction = = Partial pressure of a gas  / Total pressure

And this values are the same

The total moles of gases are:

Moles of SO + Moles of O₂ + Moles of SO₃ =

26 + 83 + 17 = 126 moles

Mole Fraction SO₃ = Moles of SO₃ / Total moles

17 / 126 = 0.135

This can be used to find out the partial pressure

Mole fraction = Partial pressure SO₃ / Total pressure

0.135 = Partial pressure  SO₃ / 0.950 atm

0.135 atm . 0.950atm = Partial pressure  SO₃

Partial pressure SO₃ = 0.128 atm

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Given the various data from the question, the answers to each question is given below:

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Avogadro's hypothesis

1 mole of K₂CrO₄ = 6.02×10²³ molecules

Therefore,

0.6 mole of K₂CrO₄ = 0.6 × 6.02×10²³

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1 mole of K₂CrO₄ contains 2 moles of K.

Therefore,

0.6 mole of K₂CrO₄ will contain = 0.6 × 2 = 1.2 mole of K

From Avogadro's hypothesis,

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1.2 mole of K = 7.224×10²³ atoms

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Molarity is defined as:

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From the question given above, we obtained the following:

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<h3>4. How to determine the volume </h3>

From the question given above, the following data were obtained:

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Percentage of sugar = (50 / 250) × 100

Percentage of sugar = 20%

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Total volume = 2 L

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Volume of vinegar =?

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Learn more about Avogadro's number:

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Now put all the values in this formula, we get the percent error.

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