Question

Suppose that at one stage in the reaction, 26.0 mol SO , 2 83.0 mol O2, and 17.0 mol SO3 are present in the reaction vessel at a total pressure of 0.950 atm. Calculate the mole fraction of SO3 and its partial pressure.

Answer 1

Answer:

- Mole fraction of SO₃ : 0.135

- Partial pressure SO₃ = 0.128 atm

Explanation:

Let's find out the mole fraction to know, what we were asked.

Mole fraction = Moles of a gas / Total moles

Mole fraction can also corresponds to Pressures, like this:

Mole fraction = = Partial pressure of a gas  / Total pressure

And this values are the same

The total moles of gases are:

Moles of SO + Moles of O₂ + Moles of SO₃ =

26 + 83 + 17 = 126 moles

Mole Fraction SO₃ = Moles of SO₃ / Total moles

17 / 126 = 0.135

This can be used to find out the partial pressure

Mole fraction = Partial pressure SO₃ / Total pressure

0.135 = Partial pressure  SO₃ / 0.950 atm

0.135 atm . 0.950atm = Partial pressure  SO₃

Partial pressure SO₃ = 0.128 atm