Answer:
![6.9\times 10^{28}m^{-3}](https://tex.z-dn.net/?f=6.9%5Ctimes%2010%5E%7B28%7Dm%5E%7B-3%7D)
Explanation:
We are given that
Diameter of wire=d=4.12 mm
Radius of wire=r![r=\frac{d}{2}=\frac{4.12}{2}=2.06mm=2.06\times 10^{-3} m](https://tex.z-dn.net/?f=r%3D%5Cfrac%7Bd%7D%7B2%7D%3D%5Cfrac%7B4.12%7D%7B2%7D%3D2.06mm%3D2.06%5Ctimes%2010%5E%7B-3%7D%20m)
![1mm=10^{-3} m](https://tex.z-dn.net/?f=1mm%3D10%5E%7B-3%7D%20m)
Current=I=8 A
Drift velocity=![v_d=5.4\times 10^{-5} m/s](https://tex.z-dn.net/?f=v_d%3D5.4%5Ctimes%2010%5E%7B-5%7D%20m%2Fs)
We have to find the density of free electrons in the metal
We know that
Density of electron=![n=\frac{I}{v_deA}](https://tex.z-dn.net/?f=n%3D%5Cfrac%7BI%7D%7Bv_deA%7D)
Using the formula
Density of free electrons=![\frac{8}{5.4\times 10^{-5}\times 1.6\times 10^{-19}\times 3.14\times (2.06\times 10^{-3})^2}](https://tex.z-dn.net/?f=%5Cfrac%7B8%7D%7B5.4%5Ctimes%2010%5E%7B-5%7D%5Ctimes%201.6%5Ctimes%2010%5E%7B-19%7D%5Ctimes%203.14%5Ctimes%20%282.06%5Ctimes%2010%5E%7B-3%7D%29%5E2%7D)
By using Area of wire=![\pi r^2](https://tex.z-dn.net/?f=%5Cpi%20r%5E2)
![\pi=3.14\\e=1.6\times 10^{-19} C](https://tex.z-dn.net/?f=%5Cpi%3D3.14%5C%5Ce%3D1.6%5Ctimes%2010%5E%7B-19%7D%20C)
Density of free electrons=![6.9\times 10^{28}m^{-3}](https://tex.z-dn.net/?f=6.9%5Ctimes%2010%5E%7B28%7Dm%5E%7B-3%7D)
A light year is a measurement of distance that is used in the space. It is the distance that a light traveled for 1 year on Earth or 365 days on Earth at a speed of 3 x 10^8 meters per second. To convert the units from light year to the SI unit meters, we simply make use of the definition of the unit. We do as follows:
18.9 light years ( 365 days / 1 light year ) ( 24 h / 1 day ) ( 3600 s / 1h ) ( 3 x 10^8 m/s) = 1.79 x 10^17 meters
Therefore, 18.9 light years is equal to 1.79 x 10^17 meters.
B) They are all sources of electricity
Hope it helps!!
Of approximately 1 to 4 kHz6 and approximately 16 kHz for mice.
<span>B?) Electric field E = q / (εo*A)
C) V = E*d = q*d / (εo*A)
D) V = q / C
so C = q / V = q * 1/V = q*εo*A / q*d = εo*A / d
I hope this helps! ^_^
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