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notka56 [123]
2 years ago
14

If the pressure exerted on a 300.0 mL sample of hydrogen gas at constant temperature is increased from 0.500 kPa to 0.750 kPa, w

hat will be the final volume of the sample?
Physics
1 answer:
uranmaximum [27]2 years ago
5 0

Answer:

200 mL

Explanation:

Given that,

Initial volume, V₁ = 300 mL

Initial pressure, P₁ = 0.5 kPa

Final pressure, P₂ = 0.75 kPa

We need to find the final volume of the sample if pressure is increased at constant temperature. It is based on Boyle's law. Its mathematical form is given by :

V\propto \dfrac{1}{P}\\\\P_1V_1=P_2V_2

V₂ is the final volume

V_2=\dfrac{P_1V_1}{P_2}\\\\V_2=\dfrac{300\times 0.5}{0.75}\\\\V_2=200\ mL

So, the final volume of the sample is 200 mL.

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A stationary charge is located between the poles of a horseshoe magnet. Is a magnetic force excerted of the charge? why?
vredina [299]

A stationary charge is located between the poles of a horseshoe magnet. The magnetic force exerted by the charge is zero.

<h3>What is charge?</h3>

Charge is the physical property of matter which cause a particle to attract or repel when placed in its field.

A stationary charged particle does not interact with a static magnetic field. A charge placed in a magnetic field experiences a magnetic force. There will be no magnetic force acting on a stationary charge. The charge must be moving in order to have magnetic force on it.

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7 0
1 year ago
What type of infant temperament is generally associated with better adjustment in adulthood?
Rashid [163]
Saying no and not throwing fits and manners.
8 0
2 years ago
Newtown third law applies to blank of objects​
fomenos

Answer:

All

Explanation:

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8 0
3 years ago
Two of the three tuning forks have known frequencies. When a 610 Hz fork and the unknown fork are struck together, four beats pe
RUDIKE [14]

-- In combination with 610 Hz, the beat frequency is 4 Hz.

So the unknown frequency is either (610+4) = 614 Hz
or else (610-4) = 606 Hz.

In combination with 605 Hz, the beat frequency will be
either (614-605) = 9 Hz or else (606-605) = 1 Hz.

-- In actuality, when combined with the 605 Hz, the beat
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So the unknown is (605+9) = 614 Hz.
 
6 0
3 years ago
Part A Determine the absolute pressure on the bottom of a swimming pool 30.0 m by 8.7 m whose uniform depth is 1.8 m . Express y
Sphinxa [80]

Answer:

17.66 kPa

Explanation:

The volume of water in the swimming pool is the product of its dimensions

V = 30 * 8.7 * 1.8 = 469.8 cubic meters

Let water density \rho = 1000 kg/m^3, and g = 9.81 m/s2 we can calculate the total weight of water in the swimming pool

W = mg = \rho V g = 1000 * 469.8 * 9.81 = 4608738 N

The area of the bottom

A = 30 * 8.7 = 261 square meters

Therefore the pressure is its force over unit area

P = F/A = 4608738  / 261 = 17658 N/m^2 or 17.66 kPa

7 0
3 years ago
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