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3 years ago

The question belongs to Electrical Engineering (Linear System).

Engineering

1 answer:

-Dominant- [34]3 years ago

5 0

I’m crying looking at that.

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When block C is in position xC = 0.8 m, its speed is 1.5 m/s to the right. Find the velocity of block A at this instant. Note th

Amanda [17]

Answer:

The answer is "2 m/s".

Explanation:

The triangle from of the right angle:

$\to (x_c-0.8)+(1.5+y_4) +\sqrt{x_c^2 + 1.5^2}= constant$

Differentiating the above equation:

$\to V_c +V_A+ \frac{X_cV_c}{\sqrt{x_c^2 +1}}=0\\\\\to 1-V_A+ \frac{0.8 \times 1.5}{\sqrt{ 0.8^2+1.5}}=0\\\\$

$\to V_A= \frac{1.2}{\sqrt{ 0.64+1.5}}+1\\\\$

$= \frac{1.2}{ 1.46}+1\\\\= \frac{1.2+ 1.46}{ 1.46}\\\\ = \frac{2.66}{1.46}\\\\= 1.82 \ \frac{m}{s}\\\\= 2 \ \frac{m}{s}$

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3 years ago

Consider a W21x93. Determine the moment capacity of the beam. Assume the compression flange is not laterally braced and that the

OLga [1]

Answer:

The answer is "828.75"

Explanation:

Please find the correct question:

For W21x93 BEAM,

$Z_x = 221.00 in^3 \\\\\to \frac{b_t}{2t_f} =4.53\\\\\to \frac{h}{t_w}=32.3$

For A992 STREL,

$F_y= 50\ ks$

Check for complete section:

$\to \frac{b_t}{2t_f} =4.53 < \frac{65}{\sqrt{f_y = 9.19}}\\\\\to \frac{h}{t_w} =32.3 < \frac{640}{\sqrt{f_y = 90.5}}$

Design the strength of beam = $\phi_b Z_x F_y\\\\$

$=0.9 \times 221 \times 50\\\\=9945 \ in \ \ kips\\\\=\frac{9945}{12}\\\\= 828.75 \ft \ kips \\$

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3 years ago

What is the ratio between driver gear A with 60 teeth and driven gear B with 180 teeth?

Anna71 [15]

The ratio between a and b is 1/3

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3 years ago

What do you think of this schematic diagram?

Sholpan [36]

Explanation:

A schematic diagram is a picture that represents the components of a process, device, or other object using abstract, often standardized symbols and lines. ... Schematic diagrams do not include details that are not necessary for comprehending the information that the diagram was intended to convey.

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What information you would gain by watching the video. Plz Help due today.

Archy [21]

Answer: It doesnt let me watch the link im sorry :(

Explanation:

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