Question

Which quadratic equation does not have a real solution? (1 point)

Answer 1

Since it has a negative discriminant, the quadratic equation that does not have a real solution is given by:

−4x2 − 4x − 6 = 0.

What is the discriminant of a quadratic equation and how does it influence the solutions?

A quadratic equation is modeled by:

$y = ax^2 + bx + c$

The discriminant is:

$\Delta = b^2 - 4ac$

The solutions are as follows:

• If $\mathbf{\Delta > 0}$, it has 2 rational solutions.

• If $\mathbf{\Delta = 0}$, it has 1 rational solutions.

• If $\mathbf{\Delta < 0}$, it has 0 real solutions.

We want $\Delta < 0$, hence, for equation -4x² - 4x - 6, we have that a = -4, b = -4, c = -6, hence:

$\Delta = (-4)^2 - 4(-4)(-6) = 16 - 96 = -80$

Negative discriminant, hence it does not have a real solution.

More can be learned about the discriminant of a quadratic function at brainly.com/question/19776811

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