Question

Please. Physics is so difficult.

Answer 1

the answer should be 0.00988 m

Answer 2

Answer:

0.010 m

Explanation:

So the equation for a pendulum period is: $y=2\pi\sqrt{\frac{L}{g}}$ where L is the length of the pendulum. In this case I'll use the approximation of pi as 3.14, and g=9.8 m\s. So given that it oscillates once every 1.99 seconds. you have the equation:

$1.99 s = 2(3.14)\sqrt{\frac{L}{9.8 m\backslash s^2}}$

Evaluate the multiplication in front

$1.99 s = 6.28\sqrt{\frac{L}{9.8m\backslash s^2}$

Divide both sides by 6.28

$0.317 s= \sqrt{\frac{L}{9.8 m\backslash s^2}}$

Square both sides

$0.100 s^2= \frac{L}{9.8 m\backslash s^2}$

Multiply both sides by m/s^2  (the s^2 will cancel out)

$0.984 m = L$

Now now let's find the length when it's two seconds

$2.00 s = 6.28\sqrt{\frac{L}{9.8m\backslash s^2}}$

Divide both sides by 6.28

$0.318 s = \sqrt{\frac{L}{9.8 m\backslash s^2}$

Square both sides

$0.101 s^2 = \frac{L}{9.8 m\backslash s^2}$

Multiply both sides by 9.8 m/s^2 (s^2 will cancel out)

$0.994 m = L$

So to find the difference you simply subtract

0.984 - 0.994 = 0.010 m