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kogti [31]
3 years ago
13

The Henry's law constant for CO2 is 3.6 ✕ 10−2 M/atm at 25°C. What pressure (in atm) of carbon dioxide is needed to maintain a C

O2 concentration of 0.19 M in a can of lemon-lime soda?
Physics
1 answer:
xeze [42]3 years ago
6 0

To solve this problem we will use Henry's law. This law states that at a constant temperature, the amount of gas dissolved in a liquid is directly proportional to the partial pressure exerted by that gas on the liquid. Mathematically it is formulated as follows:

C = K_H*P

Where,

K_H = Henry's constant for C02 at 25°C is equal to 3.6*10^{-2}M/atm

C = Gas concentration is 0.19M

Replacing we have,

0.19 M = (3.6*10^-2 M/atm)*P

P = 5.277 atm

Therefore the pressure of carbon dioxide is 5.277 atm

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A wire that is 0.65 m long and carrying a current of 8.2 A is at right angles to a uniform magnetic field. The force on the wire
Luda [366]

Answer:

0.075 T

Explanation:

When a current-carrying wire is immersed in a region with magnetic field, the wire experiences a force, given by

F=ILB sin \theta

where

I is the current in the wire

L is the length of the wire

B is the strength of the magnetic field

\theta is the angle between the direction of I and B

In this problem we have:

L = 0.65 m is the length of the wire

I = 8.2 A is the current in the wire

F = 0.40 N is the force experienced by the wire

\theta=90^{\circ} since the current is at right angle with the magnetic field

Solving the formula for B, we find the strength of the magnetic field:

B=\frac{F}{IL sin \theta}=\frac{0.40}{(8.2)(0.65)(sin 90^{\circ})}=0.075 T

3 0
3 years ago
What did Charles Darwin’s conclude on the Galapagos Island? Plz answer fast
kvasek [131]
He discovered several species of finches that varied from island to island and it helped him make his theory of natural selection.

hope this helps ! 
3 0
4 years ago
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gtnhenbr [62]
The answer would most likely be A since obviously gravity weighs things down which helps the every other masses stay settled in place
6 0
3 years ago
Read 2 more answers
Find electric field at point p which is a distance l away from the both +q and -q
denis-greek [22]

Answer:

\frac{1}{4\times(pie)\times\text{E}} \times\frac{q}{I^{2} }+\frac{1}{4\times(pie)\times\text{E}} \times\frac{-q}{I^{2} }

Explanation:

As given point p is equidistant from both the charges

It must be in the middle of both the charges

Assuming all 3 points lie on the same line

Electric Field due a charge q at a point ,distance r away

=\frac{1}{4\times(pie)\times\text{E}} \times\frac{q}{r^{2} }

Where

  • q is the charge
  • r is the distance
  • E is the permittivity of medium

Let electric field due to charge q be F1 and -q be F2

I is the distance of P from q and also from charge -q

⇒

F1=\frac{1}{4\times(pie)\times\text{E}} \times\frac{q}{I^{2} }

F2=\frac{1}{4\times(pie)\times\text{E}} \times\frac{-q}{I^{2} }

⇒

F1+F2=\frac{1}{4\times(pie)\times\text{E}} \times\frac{q}{I^{2} }+\frac{1}{4\times(pie)\times\text{E}} \times\frac{-q}{I^{2} }

8 0
4 years ago
A snail crawls at a speed of 0.0004 m/s. How long will ot take to climb a garden stick 1.6m high?​
tekilochka [14]

4000 seconds

Explanation:

speed = distance / time

0.0004m/s = 1.6m / time

Subject time

time = 1.6 / 0.0004

time = 4000 seconds.

Hope this helps. Mark as brainliest if possible. tks

5 0
3 years ago
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