<span>1: Calculate the Formal Charge of C. Carbon (C) is in group 14, so that means it has 4 valence electrons. . 2: Calculate the Formal Charge of Oxygen on the Left. . 3: Calculate the Formal Charge of Oxygen on the Right. .<span>4: Check the Overall Charge.
I hope this helps:)
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Answer:
A
Explanation:
Recall that a mole of any substance contains 6.02 × 10²³ amounts of that substance.
In other words, a mole of gold atoms contains 6.02 × 10²³ gold atoms.
Hence, by dimensional analysis, we have that:
Therefore, there is about 7.99 × 10⁻³ moles of gold present in the sample.
In conclusion, the answer is A.
It's D, all of the claims are true about oxidation reactions :)