What net force is required to cause a 12,000 kg airplane to accelerate at a rate of 5.2 m/s

Which of the following is true about the kinetic molecular theory?

velikii [3]

Answer: (B) Pressure is due to the collisions of the gas particles with the walls of the container.

Option B helps to explain the factor behind gas collision under high pressure.

Explanation: Kinetic molecular theory explains the behaviour and movement of gas particles when they are in motion. It states that gas particles are always in continuous motion and are perfectly elastic in nature.

Kinetic molecular theory can be explained using both Boyle's law and Charles's law.

•Few Assumptions of Kinetic Molecular Theory.

1. Gas particles are always in motion and they collide with the walls of their container.

2. The space occupied by a gas particles is negligible in comparison to the volume of the gas

8 0

4 years ago

Carbonyl fluoride, COF2, is an important intermediate used in the production of fluorine-containing compounds. For instance, it

lions [1.4K]

Answer: The equilibrium concentration of $COF_2$ is 0.332 M

Explanation:

We are given:

Initial concentration of $COF_2$ = 2.00 M

The given chemical equation follows:

$2COF_2(g)\rightleftharpoons CO_2(g)+CF_4(g)$

Initial: 2.00

At eqllm: 2.00-2x x x

The expression of $K_c$ for above equation follows:

$K_c=\frac{[CO_2][CF_4]}{[COF_2]^2}$

We are given:

$K_c=6.30$

Putting values in above expression, we get:

$6.30=\frac{x\times x}{(2.00-2x)^2}\\\\x=0.834,1.25$

Neglecting the value of x = 1.25 because equilibrium concentration of the reactant will becomes negative, which is not possible

So, equilibrium concentration of $COF_2=(2.00-2x)=[2.00-(2\times 0.834)]=0.332M$

Hence, the equilibrium concentration of $COF_2$ is 0.332 M

4 0

3 years ago

For the gaseous reaction of carbon monoxide and chlorine to form phosgene (COCl₂):(b) Assuming that ΔS° and ΔH° change little wi

maksim [4K]

ΔG° at 450. K is -198.86kJ/mol

The following is the relationship between ΔG°, ΔH, and ΔS°:

ΔH-T ΔS = ΔG

where ΔG represents the common Gibbs free energy.

the enthalpy change, ΔH

The temperature in kelvin is T.

Entropy change is ΔS.

ΔG° = -206 kJ/mol

ΔH° equals -220 kJ/mol

T = 298 K

Using the formula, we obtain:

-220kJ/mol -T ΔS° = -206kJ/mol

220 kJ/mol +206 kJ/mol =T ΔS°.

-T ΔS = 14 kJ/mol

for ΔS-14/298

ΔS=0.047 kJ/mol.K

450K for the temperature Completing a formula with values

ΔG° = (450K)(-0.047kJ/mol)-220kJ/mol

ΔG° = -220 kJ/mol + 21.14 kJ/mol.

ΔG°=198.86 kJ/mol

Learn more about ΔG° here:

brainly.com/question/17214066

#SPJ4

7 0

2 years ago

What does the term "basic unit of matter" refer to?

MArishka [77]

Vas happenin
Hope your day is going well
Atoms are referred to basic unit of matter
Hope this helps *smiles*

4 0

3 years ago

Read 2 more answers

Using the following equation how many grams of water you would get from 886 g of glucose:

ankoles [38]

Answer:

531.6g

Explanation:

Total moles of glucose in this case is: 886/180= 4.922 (mole)

For every 1 mole glucose we get 6 mole water

-> Mole of water is: 4.922 * 6= 29.533 (mole)

weight of water is 18. Therefore, total weight of water that we will have from 886g of glucose are: 25.933*18= 531.6g

8 0

3 years ago