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seropon [69]
3 years ago
7

If an ice cube melts at 0ºC but water also freezes at 0ºC, what is the difference between melting and freezing in terms of…….

Chemistry
1 answer:
devlian [24]3 years ago
4 0

Answer:

<em>8. When melting the energy of the ice cubes increases and when frezzing the energy of the water decreases.</em>

<em />

<em>9. When melting the otion of the particles speed up, when freezing the motion of the particles slow down.</em>

Explanation:

<em><u>8. The energy involved in the phase changes</u></em>

When an ice cube melts at 0ºC it must absorb or gain energy from the surroundings. This is an endothermic process, because the energy of the liquid water shall be higher than the energy of the starting ice cubes.

In conclusion, when melting the energy of the water increases.

On the other hand, when the liquid water freezes, also at 0ºC, the flow of heat energy is from the liquid water to the surroundings. This is an exothermic process because the water releases heat. At the end, the energy of the frozen water will be lower than the energy of the liquid water.

In conclusion, when freezing the enery of the water decreases.

<u><em>9. The motion of the particles of the substances during the phase changes</em></u>

<u><em /></u>

The particles of liquid substances are in constant motion, which is what allows them to flow. This is because the particles (molecules or atoms) are relatively distant from each other, with relatively low intermolecular forces.  Thus, they can slide on each other.

On the other hand, the solid substances have the particles in fixed position in structures called crystals. The particles vibrate but do not translation motion.

In conclusion, the difference is that the motion of the particles during melting increases and the motion of th particles during freezing decreases.

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How many moles of oxygen must be placed
umka21 [38]

Answer: 0.245 moles of oxygen must be placed in the container to exert the given pressure at the given temperature. The Ideal Gas Law equation gives the relationship among the pressure, volume, temperature, and moles of gas.

Further Explanation:

The Ideal Gas Equation is:  

PV = nRT  

where:  

P - pressure (in atm)  

V - volume (in L)  

n - amount of gas (in moles)  

R - universal gas constant 0.08206 \frac{L-atm}{mol-K}  

T - temperature (in K)  

In the problem, we are given the values:  

P = 2.00 atm (3 significant figures)

V = 3.00 L  (3 significant figures)

n = ?

T = 25.0 degrees Celsius (3 significant figures)  

We need to convert the temperature to Kelvin before we can use the Ideal Gas Equation. The formula to convert from degree Celsius to Kelvin is:  

Temperature \ in \ Kelvin = Temperature\ in \ Celsius \ + \ 273.15  

Therefore, for this problem,  

Temperature\ in \ K = 25.0 +273.15\\Temperature\ in \ K = 298.15  

Solving for n using the Ideal Gas Equation:  

n \ = \frac{PV}{RT}\\n \ = \frac{(2.00 \ atm) \ (3.00 \ L)}{(0.08206 \ \frac{L-atm}{mol-K})( 298.15 \ K)}  \\n \ = 0.245 \ mol

The least number of significant figures is 3, therefore, the final answer must have only 3 significant figures.

Learn More  

1. Learn more about Boyle's Law brainly.com/question/1437490  

2. Learn more about Charles' Law brainly.com/question/1421697  

3. Learn more about Gay-Lussac's Law brainly.com/question/6534668

Keywords: Ideal Gas Law, Volume, Pressure

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