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vivado [14]
3 years ago
10

A car traveling at a speed of 13 meters per second accelerates uniformly to a speed of 25 meters per second in 5.0 seconds. 11-

Calculate the magnitude of the acceleration of the car during this 5.0-second time interval.
Physics
1 answer:
Aleks04 [339]3 years ago
7 0

Answer:

a=2.4\ m/s^2

Explanation:

Given that,

Initial speed of a car, u = 13 m/s

Final speed of a car, v = 25 m/s

Time, t = 5 s

We need to find the acceleration of the car during this 5.0 second time interval. Let a is the acceleration. It can be calculated as :

a=\dfrac{v-u}{t}\\\\a=\dfrac{25-13}{5}\\\\=2.4\ m/s^2

So, the acceleration of the car is 2.4\ m/s^2.

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Answer:

The force is the same

Explanation:

The force per meter exerted between two wires carrying a current is given by the formula

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Substituting, we find the force per unit length on the two wires:

\frac{F}{L}=\frac{(4\pi \cdot 10^{-7})(2.79)(4.36)}{2\pi (0.0915)}=2.66\cdot 10^{-5}N

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The same conclusion comes out  from Newton's third law of motion, which states that when an object A exerts a force on an object B, then object B exerts an equal and opposite force on object A (action-reaction). If we apply the law to this situation, we see that the force exerted by wire 1 on wire 2 is the same as the force exerted by wire 2 on wire 1 (however the direction is opposite).

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Why does the biosphere not have distinct boundaries?​
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