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vivado [14]
3 years ago
10

A car traveling at a speed of 13 meters per second accelerates uniformly to a speed of 25 meters per second in 5.0 seconds. 11-

Calculate the magnitude of the acceleration of the car during this 5.0-second time interval.
Physics
1 answer:
Aleks04 [339]3 years ago
7 0

Answer:

a=2.4\ m/s^2

Explanation:

Given that,

Initial speed of a car, u = 13 m/s

Final speed of a car, v = 25 m/s

Time, t = 5 s

We need to find the acceleration of the car during this 5.0 second time interval. Let a is the acceleration. It can be calculated as :

a=\dfrac{v-u}{t}\\\\a=\dfrac{25-13}{5}\\\\=2.4\ m/s^2

So, the acceleration of the car is 2.4\ m/s^2.

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Answer:

the two vehicles will be moving at a speed of 6.16  m/s

Explanation:

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geniusboy [140]

Answer:

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soln 2

                              if 100 % = 850

therefore what about 106% = ?

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if you need any clarification or more explanation pls do mention on the comment section.i would like to help more

Hope this helps and if it does mark as branliest answer thx

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