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3 years ago

A small 22 kilogram canoe is floating downriver at a speed of 5 m/s. What's the canoes kinetic energy? _______ Joules

Physics

2 answers:

netineya [11]3 years ago

8 0

The non-relativistic formula for kinetic energy for low speeds is :

K.E = 0.5mv^2 = 0.5 * 22 * (5)^2 = 275 J

Lelu [443]3 years ago

6 0

275 joules is your answer

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A 75-g projectile traveling at 600 m /s strikes and becomes embedded in the 40-kg block, which is ini-tially stationary. Compute

levacccp [35]

Explanation:

The given data is as follows.

Mass, m = 75 g

Velocity, v = 600 m/s

As no external force is acting on the system in the horizontal line of motion. So, the equation will be as follows.

$m_{1}v_{1_{i}} = (m_{1} + m_{2})vi$

where, $m_{1}$ = mass of the projectile

$m_{2}$ = mass of block

v = velocity after the impact

Now, putting the given values into the above formula as follows.

$m_{1}v_{1_{i}} = (m_{1} + m_{2})vi$

$75(10^{-3}) \times 600 = [(75 \times 10^{-3}) + 50] \times v$

= $\frac{45}{50.075}$

v = 0.898 m/s

Now, equation for energy is as follows.

E = $\frac{1}{2}mv^{2}$

= $\frac{1}{2} \times (75 \times 10^{-3} + 50) \times (600)^{2}$

= 13500 J

Now, energy after the impact will be as follows.

E' = $\frac{1}{2}[75 \times 10^{-3} + 50](0.9)^{2}$

= 20.19 J

Therefore, energy lost will be calculated as follows.

$\Delta E$ = E E'

= (13500 - 20) J

= 13480 J

And, n = $\frac{\Delta E}{E}$

= $\frac{13480}{13500} \times 100$

= 99.85

= 99.9%

Thus, we can conclude that percentage n of the original system energy E is 99.9%.

7 0

3 years ago

Read 2 more answers

Please help me .finish this paper

Evgesh-ka [11]

Solution-1:-

$\boxed{\sf \dfrac{10\times 1000}{60\times 60}}$

Solution:-2

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Solution:-3

$\boxed{\sf 320m}$

Solution:-4

$\boxed{\sf Rough\:tiles\:are\:used\:in\:bathroom}$

Solution:-5

$\boxed{\sf Mg_3N_2}$

Solution:-6

$\boxed{\sf Grapes\:and\:Rambutan}$

Solution:-7

$\boxed{\sf {}^{}_{}N}$

Solution:-8

$\boxed{\sf Galactuse}$

Solution:-9

$\boxed{\sf Y-X}$

Solution:-10

$\boxed{\sf Cell\:wall}$

7 0

3 years ago

Assume that an intercontinental ballistic missile goes from rest to a suborbital speed of 6.50 km/s in 60.0 s (the actual speed

olasank [31]

Answer:

Average acceleration is $(11.05)g\ m/s^2$

Explanation:

It is given that,

Initial velocity, u = 0

Final velocity, v = 6.5 km/s = 6500 m/s

Time taken, t = 60 s

Acceleration, $a=\dfrac{v-u}{t}$

$a=\dfrac{v}{t}$

$a=\dfrac{6500\ m/s}{60}$

$a=108.33\ m/s^2$

Since, $g=9.8\ m/s^2$

So, $a=(11.05)g\ m/s^2$

So, the angular acceleration of the missile is $(11.05)g\ m/s^2$ . Hence, this is the required solution.

4 0

3 years ago

5. Which of these affect the brightness of a bulb? Choose all that apply.* 6 po

schepotkina [342]

Answer:

The voltage of the battery

7 0

3 years ago

Lila is a track and field athlete. She must complete four laps around a circular track. The track itself is a 400 meter track an

trapecia [35]

Answer: A. Her speed is 4.4 m/s, and her velocity is 0 m/s.

Explanation: i took the test on edgenuity

6 0

3 years ago