1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Citrus2011 [14]
2 years ago
14

Two identical 3.0-kg cubes are placed on a horizontal surface in

Physics
1 answer:
DedPeter [7]2 years ago
5 0

The magnitude of the force exerted by the left cube on the right cube is 17.64N.

<h3>What is frictional force?</h3>

When an object is moving on a rough surface, it experiences opposition. This opposing force is called the friction.

Two identical 3.0-kg cubes are placed on a horizontal surface in contact with one another. The cubes are lined up from left to right and a force F₁ is applied to the left side of the left cube causing both cubes to move at a constant speed v. The coefficient of kinetic friction between the cubes and the surface is 0.3.

From the equilibrium of forces in vertical direction

Normal force N= 2m x g

friction force f = μN =μ(2m)g

From the equilibrium of forces in horizontal direction

F₁ =ma =0

using Newton's third law of motion, we get

F₁  - f =0

F₁  =f = μ(2m)g

Put the values, we get

F₁  = 17.64N

Thus, magnitude of the force exerted by the left cube on the right cube is 17.64N.

Learn more about friction force.

brainly.com/question/1714663

#SPJ1

You might be interested in
4.-El bloque de la figura recibe las fuerzas que se muestran
Irina-Kira [14]

Answer

que?

Explanation:

4 0
3 years ago
You discover a binary star system in which one member is a 15 solar mass main-sequence star and the other star is a 10 solar mas
Sever21 [200]

Answer:

A star with 15 solar masses is too big to be a main-sequence star.

4 0
4 years ago
A mechanic pushes a 2.60 ✕ 103-kg car from rest to a speed of v, doing 5,430 J of work in the process. During this time, the car
Oduvanchick [21]

Part A. We are given that a car is pushed from rest to a final speed doing 5430 Joules of work. -

To determine the final velocity we will use the work and energy theorem which states that the work done is equal to the change in kinetic energy:

W=K_f-K_0

Since the car starts from rest this means that the initial kinetic energy is zero:

W=K_f

The kinetic energy is given by:

K=\frac{1}{2}mv^2

Substituting in the formula we get:

W=\frac{1}{2}mv_f^2

Now, we solve for the final velocity. First, we multiply both sides by 2 and divide both sides by the mass:

\frac{2W}{m}=v_f^2

Now, we take the square root to both sides:

\sqrt{\frac{2W}{m}}=v_f

Now, we plug in the values:

\sqrt{\frac{2(5430J)}{2.6\times10^3kg}}=v_f

Solving the operations:

2.04\frac{m}{s}=v_f

Therefore, the final velocity is 2.04 m/s.

Part B. Now, we use the following formula for work:

W=Fd

Where "F" is the force and "d" is the distance.

Now, we set this equation equal to the work done by the force:

Fd=5430J

Now, we divide both sides by the distance "d":

F=\frac{5430J}{29m}=187.2N

Therefore, the force exerted is 187.2 Newton.

7 0
2 years ago
A baton twirler has a baton of length 0.36 m with masses of 0.48 kg at each end. Assume the rod itself is massless. The rod is f
AleksAgata [21]

Answer:

Part a)

When rotated about the mid point

\tau = 0.021Nm

Part b)

When rotated about its one end

\tau = 0.042 Nm

Explanation:

As we know that the angular acceleration of the rod is rate of change in angular speed

so we will have

\alpha = \frac{\Delta \omega}{\Delta t}

\alpha = \frac{2.4 - 0}{3.6}

\alpha = 0.67 rad/s^2

Part a)

When rotated about the mid point

I = 2mr^2

I = 2(0.48)(0.18)^2

I = 0.0311 kg m^2

now torque is given as

\tau = 0.0311 (0.67)

\tau = 0.021Nm

Part b)

When rotated about its one end

I = m(2r)^2

I = (0.48)(0.36)^2

I = 0.0622 kg m^2

now torque is given as

\tau = (0.0622)(0.67)

\tau = 0.042 Nm

3 0
3 years ago
What is the relationship between elevation and energy
jasenka [17]

The Energy related to object motion.Potential energy most commonly refers to gravitational potential energy, which is energy associated with an object's elevation. For an object of mass m and elevation z, its potential energy is mgz where g is the gravitational constant .............. HOPE IT HELPS YOU :)

7 0
3 years ago
Other questions:
  • In a periodic table, dots around an elements symbol indicate the number of valence electrons in an atom ? True Or False
    8·2 answers
  • Henrietta is jogging on the side-walk at 3.05 m/s on the way to her physics class. Bruce realizes that she forgot her bag of bag
    6·1 answer
  • Cut out a piece of cardboard in the shape of a letter C and locate the center of mass. is it within the frame of the letter? Can
    5·1 answer
  • If a ramp were coated with a smoother surface, the ramp’s efficiency would _____. increase because friction would decrease decre
    12·1 answer
  • An adaptation of an animal in the desert might be to
    9·1 answer
  • Concept Simulation 2.3 provides some background for this problem. A ball is thrown vertically upward, which is the positive dire
    14·1 answer
  • Usain Bolt is the fastest human at 12.4 m/s. If Usain Bolt had a mass of 94kg, what was Usain Bolt’s KE?
    10·1 answer
  • A spherical conducting shell has an inner radius of 0.2 m and an outer radius of 0.4 m. There is no charge on the outer surface
    5·1 answer
  • Name three things that are NOT made of matter
    11·1 answer
  • An 80-kilogram skier slides on waxed skis along a horizontal surface of snow at constant velocity while pushing with his poles.
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!