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AveGali [126]
3 years ago
9

Describe rotational motion

Physics
1 answer:
ratelena [41]3 years ago
3 0
Rotational motion may be described analytically for bodies undergoing pure rotation.
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HELP ASAP
lakkis [162]

Answer:

I think it's D!!

cuz protons are in the atoms

3 0
3 years ago
What is the wavelength of a wave that travels at a speed of 3.0x10^8 m/s and has a frequency of 1.5x10^16 m/s?
Vlad [161]
Speed of wave = wavelength * frequency

Therefore, wavelength is 2.0 x 10^-8
5 0
3 years ago
Two floors in a building are separated by 4.1 m. People move between the two floors on a set of stairs. (a) Determine the change
Ket [755]

Answer:

a) The change in potential energy of a 3.0 kilograms backpack carried up the stairs.

b) The change in potential energy of a persona with weight 650 newtons that descends the stairs is -2665 joules.

Explanation:

Let consider the bottom of the first floor in a building as the zero reference (z = 0\,m). The change in potential energy experimented by a particle (\Delta U_{g}), measured in joules, is:

\Delta U_{g} = m\cdot g\cdot (z_{f}-z_{o}) (1)

Where:

m - Mass, measured in kilograms.

g - Gravitational acceleration, measured in meters per square second.

z_{o}, z_{f} - Initial and final height with respect to zero reference, measured in meters.

Please notice that m\cdot g is the weight of the particle, measured in newtons.

a) If we know that m = 3\,kg, g = 9.807\,\frac{m}{s^{2}}, z_{o} = 0\,m and z_{f} = 4.1\,m, then the change in potential energy is:

\Delta U_{g} = (3\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (4.1\,m-0\,m)

\Delta U_{g} = 120.626\,J

The change in potential energy of a 3.0 kilograms backpack carried up the stairs.

b) If we know that m\cdot g = 650\,N, z_{o} = 4.1\,m and z_{f} = 0\,m, then the change in potential energy is:

\Delta U_{g} = (650\,N)\cdot (0\,m-4.1\,m)

\Delta U_{g} = -2665\,J

The change in potential energy of a persona with weight 650 newtons that descends the stairs is -2665 joules.

5 0
3 years ago
Why is it that an object can accelerate while
posledela

For the same reason that you can skate around a curve at constant speed but not with constant velocity.

The DIRECTION you're going is part of your velocity, but it's not part of your speed.

If the DIRECTION changes, that's a change of velocity.

The object doesn't have to change speed to have a different velocity. A change of direction is enough to do it.

And any change of velocity is called acceleration.

3 0
3 years ago
What effect does dropping the sandbag out of the cart at the equilibrium position have on the amplitude of your oscillation?.
Ber [7]

Answer:

It has no effect on the amplitude.

Explanation:

When the sandbag is dropped, then the cart is at its maximum speed. Dropping the sand bag does not affect the speed instantly, this is because the energy remains within the system after the bag as been dropped. The cart will always return to its equilibrium point with the same amount of kinetic energy, as a result the same maximum speed is maintained.

5 0
2 years ago
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