Answer:
no, when a plastic rod is rubbed with a duster, electrons are transferred from one material to the other. The material that gains electrons becomes negatively charged. The material that loses electrons becomes positively charged.
Explanation:
The popularity of modern sports help advance a society by bringing people together.
Answer:
The correct option is;
D. Fabrication
Explanation:
A workflow flow is a detailed business process consisting of a series of required interconnected tasks in directed graph format that is executable by workflow management system.
Considering each of the options, we have
A. Work center
This consists of part of the transformation input to output. The location
B. Project
This is the unique identifier of the task to be processed
C. Assembly line
Forms part of the required input where transformation takes place and items are being processed within the assembly line
D. Fabrication
Here the item is fixed, without motion, therefore this is not considered a major work flow structure
E. Continuous flow
Here again, the items are being processed and are in motion, which constitutes a workflow structure.
Answer:
5 × 10¹⁰ or 5 billion times louder is the intensity of sound at a rock concert in comparison with that of a whisper
Explanation:
Given that at a rock concert;
the intensity of sound is 110 dB compared to a whisper of 3 dB
Now; how many times louder will that of the whisper be compared to the sound of the rock concert
Using the formula for calculating decibels (dB);
For 110 dB
dB = 10log₁₀(W)
110 dB = 
110 dB = 10¹¹
For 3dB
dB = 10log₁₀(W)
3 dB = 
3 dB = 2
Now:
(110/3)dB = 10¹¹/2
(110/3)dB = 5 × 10¹⁰ or 5 billion times louder is the intensity of sound at a rock concert in comparison with that of a whisper
Answer:
<h2>
E = 2.8028*10⁻¹⁹ Joules</h2>
Explanation:
The minimum energy needed to eject electrons from a metal with a threshold frequency fo is expressed as E = hfo
h = planck's constant
fo = threshold frequency
Given the threshold frequency fo = 4.23×10¹⁴ s⁻¹
h = 6.626× 10⁻³⁴ m² kg / s
Substituting this value into the formula to get the energy E
E = 4.23×10¹⁴ * 6.626 × 10⁻³⁴
E = 28.028*10¹⁴⁻³⁴
E = 28.028*10⁻²⁰
E = 2.8028*10⁻¹⁹ Joules
