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faust18 [17]
3 years ago
14

HELP!!! FAST!!

Physics
1 answer:
7nadin3 [17]3 years ago
8 0
Im think its A. A release of a large amount 9f energy
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Why are antennas needed for radio, television, and cell phone transmission>
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Answer:

A.without a long antenna, 're signal will not travel far

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3 years ago
Scientists have changed the model of the atom as they have gathered new evidence. One of the atomic models is shown below.
yawa3891 [41]

Answer:

B: The colors of light emitted from heated atoms had very specific energies.

Explanation:

In Thompson's model of an atom the atom is said to be constituted of electrons which are surrounded by a haze of positive charge in order to balance the electrons' negative charges. It is also called plum prodding model because of negatively charged plums which are surrounded by the positively charged pudding.

Now, as the electrons move from higher to lower energy levels a photon which is a particle of light will be given off.

Thus, the correct answer is option B

7 0
4 years ago
A +35 µC point charge is placed 46 cm from an identical +35 µC charge. How much work would be required to move a +0.50 µC test c
Ira Lisetskai [31]

Answer:

512.5 mJ

Explanation:

Let the two identical charges be q = +35 µC and distance between them be r₁ = 46 cm. A charge q' = +0.50 µC located mid-point between them is at r₂ = 46 cm/2 = 23 cm = 0.23 m.

The electric potential at this point due to the two charges q is thus

V = kq/r₂ + kq/r₂

= 2kq/r₂

= 2 × 9 × 10⁹ Nm²/C² × 35 × 10⁻⁶ C/0.23 m

= 630/0.23  × 10³ V

= 2739.13 × 10³ V

= 2.739 MV

When the charge q' is moved 12 cm closer to either of the two charges, its distance from each charge is now r₃ = r₂ + 12 cm = 23 cm + 12 = 35 cm = 0.35 m and r₄ = r₂ - 12 cm = 23 cm - 12 cm = 11 cm = 0.11 cm.

So, the new electric potential at this point is

V' = kq/r₃ + kq/r₄

= kq(1/r₃ + 1/r₄)

= 9 × 10⁹ Nm²/C² × 35 × 10⁻⁶ C(1/0.35 m + 1/0.11 m)

= 315 × 10³(2.857 + 9.091) V

= 315 × 10³ (11.948) V

= 3763.62 × 10³ V

= 3.764 MV

Now, the work done in moving the charge q' to the point 12 cm from either charge is

W = q'(V' - V)

= 0.5 × 10⁻⁶ C(3.764 MV - 2.739 MV)

= 0.5 × 10⁻⁶ C(1.025 × 10⁶) V

= 0.5125 J

= 512.5 mJ

8 0
3 years ago
What happens to the forces acting on a falling object at terminal velocity?
xenn [34]

Answer: Objects falling through a fluid eventually reach terminal velocity. At terminal velocity, the object moves at a steady speed in a constant direction because the resultant force acting on it is zero.

8 0
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A comet speeds up as it approaches the Sun. Which statement about its kinetic energy is correct?(1 point)
krok68 [10]

A comet speeds up as it approaches the Sun. Which statement about its kinetic energy is correct option is - (1) The comet has no kinetic energy because it is in outer space.

  • Large ice and dust-based bodies known as comets circle the Sun. These ancient objects, which are best known for their long, streaming tails, are relics from the solar system's birth 4.6 billion years ago. The majority of comets are located outside of our solar system. Some are found in the Kuiper Belt, a vast disc that extends past Neptune's orbit. These are known as short-period comets. They orbit the Sun in lesser than 200 years.
  • The Outermost Layer, the solar system's sphere-shaped outer edge, which is nearly 50 times further from the Sun than the Kuiper Belt, is home to additional comets. Because of how much longer it takes them to orbit the Sun, these are known as long-period comets. The comet with the longest known orbit completes one orbit in excess of 250,000 years.

To know more about comet

brainly.com/question/8705662

#SPJ1

6 0
1 year ago
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