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faust18 [17]
3 years ago
14

HELP!!! FAST!!

Physics
1 answer:
7nadin3 [17]3 years ago
8 0
Im think its A. A release of a large amount 9f energy
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A vector A has a magnitude of 5 units and points in the −y-direction, while a vector B has triple the magnitude of A and points
Harman [31]

Answer:

A+B; 5√5 units, 341.57°

A-B; 5√5 units, 198.43°

B-A; 5√5 units, 18.43°

Explanation:

Given A = 5 units

By vector notation and the axis of A, it is represented as -5j

B = 3 × 5 = 15 units

Using the vector notations and the axis, B is +15i. The following vectors ate taking as the coordinates of A and B

(a) A + B = -5j + 15i

A+B = 15i -5j

|A+B| = √(15)²+(5)²

= 5√5 units

∆ = arctan(5/15) = 18.43°

The angle ∆ is generally used in the diagrams

∆= 18.43°

The direction of A+B is 341.57° based in the condition given (see attachment for diagrams

(b) A - B = -5j -15i

A-B = -15i -5j

|A-B|= √(15)²+(-5)²

|A-B| = √125

|A-B| = 5√5 units

The direction is 180+18.43°= 198.43°

See attachment for diagrams

(c) B-A = 15i -( -5j) = 15i + 5j

|B-A| = 5√5 units

The direction is 18.43°

See attachment for diagram

5 0
3 years ago
Which type of bond and how many bonds would occur as carbon dioxide (CO2) is formed from carbon in Group IVA and oxygen in Group
Rus_ich [418]

Answer:

The answer is D. Four covalent bounds

5 0
3 years ago
What's the simplest approach to solve a physics dimensional question ​
Darina [25.2K]

Explanation:

<em><u>If Q is the unit of a derived quantity represented by Q = MaLbTc, then MaLbTc is called dimensional formula and the exponents a, b and, c are called the dimensions.</u></em>

please subscribe my mom's channel

7 0
3 years ago
Two blocks, stacked one on top of the other, slide on a frictionless horizontal surface. The surface between the two blocks is r
devlian [24]

Answer:

F_{net} = 31.88 N

Explanation:

When top block is just or about to slide on the lower block then we can say that the frictional force on it will be maximum static friction

So we will have

F_{net} = ma

F_s = ma

\mu_s mg = ma

a = \mu_s g

a = (0.50)(9.81)

a = 4.905 m/s^2

now for the Net force on two blocks to move together

F_{net} = (m_1 + m_2) a

F_{net} = (2.3 + 4.2)(4.905)

F_{net} = 31.88 N

4 0
3 years ago
Help! 20 points of a test!
mamaluj [8]

Answer:

t=6

Explanation:

Multiply to remove the variable from the denominator.

4 0
3 years ago
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