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Sedbober [7]
3 years ago
6

Describe how to use cleaning tools and equipment safely and properly

Engineering
1 answer:
Andreas93 [3]3 years ago
5 0

Answer:

to use cleaning tools safe its save to read what there made of its safe not to use to much of the product its also save to use gloves and goggles for some other products

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Product service life is determined by a. estimates b. market forces c. liability d. property tests e. failure analysis f. all of
4vir4ik [10]

Answer: d) property tests

Explanation: Product service life can be referred as the life that define the service that can be provided by the product manufactured.The service life contains the testing and calculation of the product's quality, reliability, maintenance factor etc. These factors are known as the property of the product and so is calculated by the property test. Therefore option (d) is the correct option because other option does not define the factors for defining the product service life.

4 0
3 years ago
Choose the best compression ratio for an Otto cycle reciprocating engine: a. 5 b. 10 c. 15 d. 20
MArishka [77]

Answer:

b)10

Explanation:

We know that in Otto cycle there are four process .In first process mass of air fuel mixture enters in the cylinder.In second process that intake mass is compresses up to a specified limit.In general compression ratio in Otto cycle is about 9 or 10.In third process burning of fuel takes place where certain amount of work is obtained.Last process is exhaust process in which burning gas escape out from the cylinder.

Best compression ratio in Otto cycle is about 10.Beyond this value of compression ratio the cycle will not proved best work out put. So our option b is right.

6 0
4 years ago
The relatonship between Kalven and celsius______
umka2103 [35]

Answer:

K=C+273.15

Explanation:

Kelvin's climbing represents the <em>absolute temperature</em>. Temperature is a measure of the molecular kinetic energy of translation. If the molecules move quickly, with the same energy as in the walls of the container, which makes us feel like "heat". If the molecules do not move, the temperature is zero. 0 K.

The Celsius scale has an <em>artificial zero</em>, defined in the solidification temperature of the water. It is very useful to talk about the weather, and about some simpler technical matters. But it is artificial.

3 0
4 years ago
Find the diameter of the test cylinder in which 6660 N force is acting on it with a modulus of elasticity 110 x 103 Pa. The init
Shtirlitz [24]

Answer:

The diameter of the test cylinder should be 7.65 meters.

Explanation:

The Hooke's law relation between stress and strain is mathematically represented as

Stress=E\times strain\\\\\sigma =e\times \epsilon

Where 'E' is modulus of elasticity of the material

Now by definition of strain we have

\epsilon =\frac{\Delta L}{L_{o}}

Applying values to obtain strain we get

\epsilon =\frac{0.5}{380}=0.001316

Thus the stress developed in the material equals

\sigma = 110\times 10^{3}\times 0.001316=144.76N/m^{2}

Now by definition of stress we have

\sigma =\frac{Force}{Area}\\\\\therefore Area=\frac{Force}{\sigma }\\\\\frac{\pi D^{2}}{4}=\frac{6660N}{144.76}=46m^{2}

Solving for 'D' we get

D=\sqrt{\frac{4\times 46}{\pi }}=7.653meters

6 0
3 years ago
Calculate the energy in kJ added to 1 ft3 of water by heating it from 70° to 200°F.
Serga [27]

Answer:

The energy in kJ is 8558.16 kJ.

Explanation:

Data presented in the problem:

Water is heated from 70 (T1) to 200 °F (T2).

Volume (V) of the water is 1 ft3.

It is required for the specific heat of water(HW), which is 1 BTU/lb°F.

First, we need to calculate the mass of water (M) presented in the process. Water density (D) is 62. 4 lb/ft3.

M = V*D = (1ft3)*(62.4 lb/ft3) = 62.4 lb Water.

.After that, we can calculate the heat required (Q).

Q = M*HW*(T2 - T1) = (62.4 lb)*(1 BTU/lb°F)(200 °F - 70°F)

Q = 62.4 * 130 BTU = 8112 BTU.

Q is converted to kJ units using the conversion factor 1 BTU = 1.055 kJ

Q = 8112 BTU * (1.055 kJ/1BTU) = 8558.16 kJ.

Finally, the energy required is 8558.16 kJ.

3 0
3 years ago
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